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algol13
3 years ago
15

If GE is the angle bisector of < HGF find m. A. 6 B. 8 C. 9 D. 31

Mathematics
1 answer:
dlinn [17]3 years ago
8 0

Answer:

b

Step-by-step explanation:

hjfbxosnodjhxjdbodbdidbjdhdodhdidhidjdbdibdidbfi

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Malik wrote 18 ➗6 = 3. Which problem can he solve using this equation?
ki77a [65]

Answer: Anything for example:

Malik has 6 friend, he wants to equally give them some of the 18 cookies he back earlier that morning. How much will he give each person?

Step-by-step explanation: And the answer will be 3

6 0
2 years ago
Read 2 more answers
What’s is the gcf 33c,55cd
Juli2301 [7.4K]
The GCF of 33c and 55cd is

33c/11c = 3
55cd/11c = 5d

the greatest common factor is 11c 

hope this helps
4 0
3 years ago
What is the solution to the system of equations represented by these two lines?
Andrei [34K]

Answer:

(3,2)

Step-by-step explanation:

this is an intersecting lines which means it has one solution

8 0
2 years ago
Evaluate the following integral using trigonometric substitution
serg [7]

Answer:

The result of the integral is:

\arcsin{(\frac{x}{3})} + C

Step-by-step explanation:

We are given the following integral:

\int \frac{dx}{\sqrt{9-x^2}}

Trigonometric substitution:

We have the term in the following format: a^2 - x^2, in which a = 3.

In this case, the substitution is given by:

x = a\sin{\theta}

So

dx = a\cos{\theta}d\theta

In this question:

a = 3

x = 3\sin{\theta}

dx = 3\cos{\theta}d\theta

So

\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}

We have the following trigonometric identity:

\sin^{2}{\theta} + \cos^{2}{\theta} = 1

So

1 - \sin^{2}{\theta} = \cos^{2}{\theta}

Replacing into the integral:

\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C

Coming back to x:

We have that:

x = 3\sin{\theta}

So

\sin{\theta} = \frac{x}{3}

Applying the arcsine(inverse sine) function to both sides, we get that:

\theta = \arcsin{(\frac{x}{3})}

The result of the integral is:

\arcsin{(\frac{x}{3})} + C

8 0
3 years ago
What is the median of the data displayed in this box-and-whisker plot?
Vilka [71]
The median is 41. i hope this helps.
6 0
3 years ago
Read 2 more answers
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