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andriy [413]
4 years ago
11

Which model of earth's interior does this image show? if u answer i'll give u a thanks

Physics
1 answer:
lana66690 [7]4 years ago
4 0
It shows the inner core, core, mantle, and crust
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Type the correct answer in each box. Use numerals instead of words.
ser-zykov [4K]

Answer:

6.23 newtons per second?

Explanation:

4 0
3 years ago
URGENT PLEASE HELP!!!!! A spring has a spring constant of 105 N/m. If you compress the spring 0.1 m past its natural length, wha
konstantin123 [22]
I believe it is 10.5?? 
6 0
4 years ago
Read 2 more answers
What is the effective resistance r of the two-resistor system? express the effective resistance in terms of r1 and r2?
Alekssandra [29.7K]

As per the question, the resistor system contains two resistors.

The two resistors are denoted as r_{1}\ and\ r_{2}\ respectively

We are asked to calculate the effective resistance in terms of  r_{1}\ and\ r_{2}\ respectively

The two resistors can be connected in two ways.

CASE-1: Let the resistors are connected in series.

When the resistors are connected in series, the effective resistance is the algebraic sum of the individual resistors.

Hence, the effective resistance  r= r_{1} +r_{2}  [ans]

CASE-2: Let the resistors are connected in parallel.

The effective resistance is calculated as follows-

                                     \frac{1}{r}= \frac{1}{ r_{1}}+ \frac{1}{r_{2}}

                                            =\frac{r_{1}+ r_{2}} {r_{1} r_{2}}

                                   ⇒  r =\frac{r_{1} r_{2}} { r_{1} +r_{2}}  [ans]

4 0
4 years ago
HELP PLEASE!
ryzh [129]

Answer:

I think the second one! So sorry if it's wrong!

Explanation:

Because if it's sitting motionless, then nothing is happening to it.

7 0
3 years ago
A proton, moving in a uniform magnetic field, moves in a circle perpendicular to the field lines and takes time T for each circl
xxMikexx [17]

Answer:

option (B)

Explanation:

mass of proton, m = m

charge of proton, q = e

Time period, T = T

Initially the speed of proton is v.

The time period of the proton when it is moving in magnetic field perpendicular to the direction of magnetic field is given by

T=\frac{2\pi r}{v}

Where, r be the radius of circular path.

The relation between r and the speed v is given by

r=\frac{mv}{Bq}

Where, B be the strength of magnetic field. Substitute this value of r in the expression of time period

T=\frac{2\pi mv}{Bqv}=\frac{2\pi m}{Bq}

Here, we observe that the expression for the time period is independent to v and r so, as we change the velocity, the time period remains same.

6 0
3 years ago
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