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marissa [1.9K]
4 years ago
5

Which of the following is not a step toward planning your goals?

Physics
1 answer:
sammy [17]4 years ago
3 0

C. Disregard a goal if you don’t achieve it

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"a ________ is a mushroom-shaped pluton that forms by injecting magma between sedimentary strata, forcing the upper layers to ar
Tamiku [17]
Laccolith is a mushroom-shaped pluton that forms by injecting magma between sedimentary strata, forcing the upper layers to arch upward.
3 0
4 years ago
Read 2 more answers
f 720-nm and 620-nm light passes through two slits 0.68 mm apart, how far apart are the second-order fringes for these two wavel
valkas [14]

Answer:

0.0003 m = 0.3 mm

Explanation:

For constructive interference in the Young's experiment.

The position of the mth fringe from the central fringe is given by

y = L(mλ/d)

λ = wavelength = 720 nm = 720 × 10⁻⁹ m

L = distance between slits and screen respectively = 1.0 m

d = separation of slits = 0.68 mm = 0.68 × 10⁻³ m

m = 2

y = 1(2 × 720 × 10⁻⁹/(0.68 × 10⁻³) = 0.00212 m = 2.12 mm

For the 620 nm light,

y = 1(2 × 620 × 10⁻⁹/(0.68 × 10⁻³) = 0.00182 m = 1.82 mm

Distance apart = 2.12 - 1.82 = 0.3 mm = 0.0003 m

8 0
3 years ago
If a mass of 76 kg acts downward 0.38 m from the axis of rotation on one end of a board and another force of 129 N also acts dow
Semenov [28]

Answer:

y = 2.196 m

Explanation:

Mass, m = 76 kg

distance from axis of rotation, x = 0.38 m

Second Force, F = 129 N

moment arm of the second force, y = ?

Now, equating moments for the equilibrium

So,

m g × x = F x y

76 x 0.38 x 9.81 = 129 x y

y = \dfrac{76\times 0.38\times 9.81}{129}

y = 2.196 m

Hence, the length of the moment arm is equal to 2.196 m.

6 0
3 years ago
Can God make a rock that He can't carry?
Xelga [282]

Answer:

The answer to the question lies in the character of God. God is either finite or infinite. If God is finite and limited, then God could make a rock He could not lift. If God is unlimited in power, then He could create a rock of any size and weight and still be able to lift it.

Explanation:

8 0
2 years ago
Calculate the pressure exerted by 11.1 moles of neon gas in a volume of 5.45 L at 25°C using (a) the ideal gas equation and (b)
Ilia_Sergeevich [38]

Answer:

49.82414 atm

50.74675 atm

Explanation:

P = Pressure

V = Volume = 5.45 L

R = Gas constant = 0.08205 L atm/mol K

T = Temperature = 25°C

a = 0.211 atm L²/mol²

b = 0.0171 atm L²/mol²

From ideal gas law we have

PV=nRT\\\Rightarrow P=\dfrac{nRT}{V}\\\Rightarrow P=\dfrac{11.1\times 0.08205(273.15+25)}{5.45}\\\Rightarrow P=49.82414\ atm

The pressure is 49.82414 atm

From Van der Waals equation we have

\left(P+\frac{an^2}{V^2}\right)\left(v-nb\right)=nRT\\\Rightarrow P=\dfrac{nRT}{V-nb}-\dfrac{an^2}{V^2}\\\Rightarrow P=\dfrac{11.1\times 0.08205\times (273.15+25)}{5.45-(11.1\times 0.0171)}-\dfrac{0.211\times 11.1^2}{5.45^2}\\\Rightarrow P=50.74675\ atm

The pressure is 50.74675 atm

3 0
3 years ago
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