Ask question

Ask question

All categories

Dmitry_Shevchenko [17]

4 years ago

7

A TV is rated at 0.1 kW. This TV is used 3 hours per day. How many hours is the TV Used per month (assuming there are 30 days in

a month)?
A. 90 hours per month

B. 0.3 hours per month

C. 3 hours per month

1 answer:

elena-s [515]4 years ago

5 0

Answer:

A. 90 hours per month

Explanation:

If the T.V is used 3 hours per day

then in one month 30×3 hours

i.e, equals to 90 hours

✌️:)

You might be interested in

Willing to give out Brainliest: 3.00 m^3 of water is at 20.0°C If you raise its temperature to 60.0°C, by how much will its volu

lozanna [386]

Answer:

The answer is below

Explanation:

Charlee's law states that the volume of a gas is directly proportion to the temperature of the gas at constant pressure. That is:

V = kT, where V = volume and T = temperature, k = constant. Therefore:

V / T = k

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Given that: $V_1=3\ m^3, T_1=20^oC=(20 + 273)K=293\ k,T_2=60^oC=(60 + 273)K=333\ k.\\\\\frac{V_1}{T_1}=\frac{V_2}{T_2}\\\\\frac{3}{293}=\frac{V_2}{333} \\\\V_2=\frac{3}{293}*333\\\\V_2=3.41\ m^3\\$

The new volume is 3.41 m³. That is it expands by 0.41 m³

4 0

3 years ago

Read 2 more answers

If you lift a 16 kg child from the floor to her bed, which is 1 meter high, how much have you increased her potential energy.

Amanda [17]

GPE=mgh
GPE=16•9.8•1

6 0

3 years ago

Standing waves can be established within a cylindrical volume. However, it is not known if the volume is closed at both ends, op

Evgen [1.6K]

The frequencies are missing in the question. The three successive resonance frequencies within the volume are $f_1, f_2 \text{ and}\ f_3$ .

Solution :

Let the volume be : v

The frequency for one end open and one end closed is given by :

So, $f_n = \frac{(2n-1)v}{4L}$

Therefore,

$f_1 = \frac{v}{4L}$ , $f_2 = \frac{3v}{4L}$ , $f_3 = \frac{5v}{4L}$

So, $f_2 - 3f_1$ and $f_3=\frac{5}{3}f_2$

Therefore, the ratio of $\frac{f_3}{f_2}=\frac{5}{3}$ which is not a whole number.

Now the frequency for open volume and closed at both end

$f_n=\frac{nv}{4L}$

So, $f_1=\frac{v}{4L}$ , $f_2 = 2f_1$ , $f_2=3f_1$

From above formulae we can see that ratio of is not a whole number that is a identification for the frequency of the volume at one end open and one end closed.

Also ratio of the consecutive frequency of the volume at open from both side and closed from both side is always a whole number.

4 0

3 years ago

Two long parallel wires each carry 2.2 A in the same direction, with their centers 1.8 cm apart.A. Find the magnitude of the mag

Butoxors [25]

Answer:

Explanation:

A )

Magnetic field due to a long wire

B = (μ₀ / 4 π ) x( 2i / r )

= 10⁻⁷ x 2 i / r

where i is current , r is distance of point from the wire

Magnetic field at a point in between the wire will be total of magnetic field generated by both the wires

= 10⁻⁷ [ ( 2 x 2.2 / .009 - 2 x 2.2 / .009 ) ]

= 0

The magnetic field acts in opposite direction so they cancel out each other .

B )

At this point their magnetic field will add up

Net magnetic field

= 10⁻⁷ [ ( 2 x 2.2 / .018 + 2 x 2.2 / .036 ) ]

= 10⁻⁷ [ ( 244.44 + 122.22 ) ]

= 10⁻⁷ x 366.66

= 366.66 x 10⁻⁷ T .

C ) Force on a wire in a magnetic field = BiL where B is magnetic field , i is current and L is length of the wire . If length is one then

force = Bi

magnetic field on each wire

= B = (μ₀ / 4 π ) x( 2i / r )

= 10⁻⁷ x 2 x 2.2 / .018

= 244.44 x 10⁻⁷ T

force on each per unit length

= Bi

= 244.44 x 10⁻⁷ x 2.2

= 537.77 x 10⁻⁷ N /m

This is force of interaction between the two wires . Since direction of current is same , they will attract each other .

8 0

4 years ago

What is the electric flux φ through each of the six faces of the cube? Use ϵ0 for the permittivity of free space?

exis [7]

If total charge Q is enclosed in the surface of cube

then we will have say that total flux linked with all surfaces of the cube will be given by

$\phi = \frac{Q}{\epsilon_0}$

since the position of charge is symmetric with respect to the center of the cube so here this whole flux will be equally linked with each of the face of the cube

So here total 6 faces of the cube is there and the total flux of the charge will equally divide in these 6 faces

so flux linked with each face is given by formula

$\phi = \frac{Q}{6\epsilon_0}$

so each face will have above flux due to central position of charge Q

3 0

3 years ago