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Licemer1 [7]
3 years ago
6

¿Con qué velocidad viaja una onda formada en una cuerda de 10 m de longitud y 1 kg de masa, si se le sostiene con una tensión de

40N?

Physics
1 answer:
slavikrds [6]3 years ago
7 0
This is a picture I took

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What is the momentum of a bird with a mass of 1 kg and a velocity of 5m/s
Hoochie [10]
It could be one of this 0.2m/s/s
or 0.5m/s/s.
7 0
3 years ago
Un auto de 1000 kg que lleva una velocidad de 72 km/h se detiene en una distancia de 100 metros cuando se le aplican los frenos.
Flura [38]

Answer:

a)    F = 2000 N , B)   x = 25 m

Explanation:

a) To solve this exercise we can use the relationship between work and kinetic energy

          W = ΔK

The job is

           W = -F x

the negative sign is because the force of the brakes is contrary to the movement

as the car stops its final kinetic energy is zero

           K = ½ m v²

let's substitute

         - F x = 0 - ½ m v²

            F = ½ m v² / x

Let's reduce the magnitudes to the SI system

           v = 72 km / h (1000m / 1km) (1 h / 3600 s) = 20 m / s

let's calculate

          F = ½ 1000 20²/100

          F = 2000 N

b) x = ½ mv2 / F

let's slow down to the SI system

         v = 36 km / h = 10 m / s

let's calculate

             x = ½ 1000 10²/2000

             x = 25 m

6 0
3 years ago
Identrying the speed of the Cart
aleksklad [387]

The speed of the cart after 3 seconds of Low fan speed is equal to 54 cm/s.

<h3>How to calculate the speed?</h3>

Mathematically, speed can be calculated by using this formula;

Speed = distance/time

At Low fan speed after 3 seconds, the distance covered is 162 cm:

Speed = 162/3

Speed = 54 cm/s.

At Medium fan speed after 5 seconds, the distance covered is 600 cm:

Speed = 600/5

Speed = 120 cm/s.

At High fan speed after 2 seconds, the distance covered is 128 cm:

Speed = 128/2

Speed = 64 cm/s.

Read more on speed here: brainly.com/question/17350470

#SPJ1

6 0
2 years ago
Read 2 more answers
You shoot an arrow into the air. Two seconds later (2.00 s) the arrow has gone straight upward to a height of 35.0 m above its l
sdas [7]

This question can be solved by using the equations of motion.

a) The initial speed of the arrow is was "9.81 m/s".

b) It took the arrow "1.13 s" to reach a height of 17.5 m.

a)

We will use the second equation of motion to find out the initial speed of the arrow.

h= v_it + \frac{1}{2}gt^2\\

where,

vi = initial speed = ?

h = height = 35 m

t = time interval = 2 s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

35\ m = (v_i)(2\ s)+\frac{1}{2}(9.81\ m/s^2)(2\ s)^2\\\\v_i(2\ s)=19.62\ m\\\\v_i = \frac{19.62\ m}{2\ s}

<u>vi =  9.81 m/s</u>

b)

To find the time taken by the arrow to reach 17.5 m, we will use the second equation of motion again.

h= v_it + \frac{1}{2}gt^2\\

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 17.5 m

vi = initial speed = 9.81 m/s

t = time = ?

Therefore,

17.5 = (9.81)t+\frac{1}{2}(9.81)t^2\\4.905t^2+9.81t-17.5=0

solving this quadratic equation using the quadratic formula, we get:

t = -3.13 s (OR) t = 1.13 s

Since time can not have a negative value.

Therefore,

<u>t = 1.13 s</u>

Learn more about equations of motion here:

brainly.com/question/20594939?referrer=searchResults

The attached picture shows the equations of motion in the horizontal and vertical directions.

4 0
2 years ago
A suspended object A is attracted to a charged object B, can one conclude that A is charged? Explain
irinina [24]

Explanation:

In my view, when the Object A is attracted to a Charged object B. Object B should be Negatively or Positively charged. So Object B should be the Opposite charged according to the Object B

Example =

If Object B is Negatively Charged, the Object A should be Positively Charged

If the Object B is Positively Charged, the Object A should be Negatively Charged

Sometimes it can Mix as a Neutral as well

Hope this Helps

5 0
3 years ago
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