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Serhud [2]
3 years ago
6

The standard reduction potential for i2/i– is +0.54v, and the standard reduction potential for br2/br- is +1.07v. which reaction

occurs when bromine is added to an aqueous solution of iodide ions?
Chemistry
1 answer:
hammer [34]3 years ago
7 0
The standard reduction potential of Br2/Br- is higher than that of I2/I-, which means Br2 has a higher tendency of gaining an electron and forming Br- than I2 does.  Therefore when Br2 and I- are present in the same solution, Br2 will gain electrons from I- and form Br-, meanwhile I- loses electrons and forms I2.

Br2 + 2I- = 2Br- + I2
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What is the volume of 193 g of gold
Greeley [361]
Remember:
Density = mass/volume
Volume = mass/density
Volume = 193 g/ 19.3 g cm ^ -3
Volume = 10 cm^3
6 0
3 years ago
6. At a glance, it appears like the law of
Mamont248 [21]

Energy and mass equivalence

Explanation:

The law of conservation of energy does not apply to nuclear reactions, the law of conservation of mass-energy makes more sense in this regard.

In nuclear reactions mass is transformed into energy. Therefore, it does not conform with the law of conservation of energy.

  • According to the law of conservation of energy "energy is neither created no destroyed but they are transformed from one form to another. "
  • In nuclear reactions, mass is usually lost. Mass is not conserved.
  • But, the mass is converted into energy and we say there is mass and energy equivalence for nuclear reactions.

Learn more:

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4 0
3 years ago
FREE BRAINIEST WHO WANTS IT?!!!
tia_tia [17]

Ngl, I really want it! But how do I know you're not scamming?

8 0
3 years ago
Read 2 more answers
7. State the relationship between the concentration of ions and the boiling point for these solutions.
balu736 [363]

Answer:

  • 7. Linear relationship.

  • 8. Because ions carry charge that can move freely in solution.

  • 9. Solute: NaCl

            Solvent: H₂O

Explanation:

7. Elevation of the boling point.

The elevation of the boiling point of a solution respect to the pure solvent is a colligative property, meaning that it is proportional to the concentration of the solute particles.

        \Delta T_b=K_b\times i\times C

        T_b=T_b^0+K_b\times i\times C

Where, ΔTb is the elevation on the boiling point, Tb is the (elevated) boiling of the solution, point, Tb° is the boiling point of the pure solvent, i is the Van't Hoof factor, and C is the molal concentration (molality)

Thus the relation of the boiling point with the mola concentration (molality) is linear.

Using the table and some calculations, you can determine this relationship:

Trial  Mass of water   mass NaCl    moles NaCl     m             Tb

             kg                      g                   mol            mol/kg       ºC

  1        0.1                     8.76              0.15               1.5             101.5

 2        0.1                    17.52             0.30              3.0             103.1

 3        0.1                    20.28            0.45              4.5             104.6

 4        0.1                   35.04             0.60              6.0             106.1        

The number of moles for each trial were determinated dividing the mass in grams of the solute by the molar mass (58.44g/mol).

The molality concentrations (mole of solue per kg of solvent) were determined dividing the number of moles of each trial by the amount of solvent in kg.

As you see in the table, the column of Tb increases by an approximate constant value of 1.5ºC and the column of the molal concentration increases at a constant value of 0.15mol. Thus there is a constante rate of change of 1.5ºC/0.15mol = 10ºC/mol.

Since a constant rate of change means constant slope, this you conclude that the relationship is linear.

8. Ability to conduct an electric current.

Electric current is the flow of charges.

Ions are charged particles. There are positive ions (cations) and negative ions (ions) dissolved; this is, they are free to move in solution.

Current is the rate of flow of the charge, thus the greater the number of ions in solution, the greater the flow of charge, which is a greater current.

That explains why the greater the concentration of the ions in the solution the greater the abiity fo the solution to conduct electricity.

Pure water has a low concentration of ions (H⁺ and OH⁻) thus it has a very low ability to conduct electricity. But adding a solute, like an acid, a base, or a salt (like NaCl in this case), increases the number of ions in solution, and thus a solution with a high concetration of solute will have a great ability to conduct electricity.

9. Identify the solute and solvent.

  • The<em> solute </em>is the component of a solutions that is present in relatively small quantities and is dissolved. In this case the solute is the salt, sodium chloride, NaCl.

  • The <em>solvent</em> is the component of the solution that is present in greater amount and is able to dissolve the solute. In this case the solvent is water, H₂O.

The concentrations of the solute normally are relatively low, because they are the component with less particles in the solution.

5 0
3 years ago
In the titration of 50. 0 mL of 0. 400 M HCOOH with 0. 150 M LiOH, how many mL of LiOH are required to reach the equivalence poi
mart [117]

The volume of the 0.15 M LiOH solution required to react with 50 mL of 0.4 M HCOOH to the equivalence point is 133.3 mL

<h3>Balanced equation </h3>

HCOOH + LiOH —> HCOOLi + H₂O

From the balanced equation above,

The mole ratio of the acid, HCOOH (nA) = 1

The mole ratio of the base, LiOH (nB) = 1

<h3>How to determine the volume of LiOH </h3>
  • Molarity of acid, HCOOH (Ma) = 0.4 M
  • Volume of acid, HCOOH (Va) = 50 mL
  • Molarity of base, LiOH (Mb) = 0.15 M
  • Volume of base, LiOH (Vb) =?

MaVa / MbVb = nA / nB

(0.4 × 50) / (0.15 × Vb) = 1

20 / (0.15 × Vb) = 1

Cross multiply

0.15 × Vb = 20

Divide both side by 0.15

Vb = 20 / 0.15

Vb = 133.3 mL

Thus, the volume of the LiOH solution needed is 133.3 mL

Learn more about titration:

brainly.com/question/14356286

8 0
2 years ago
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