The difference between the initial mass (1.04 g) and the final mass (0.61g) is the mass of water present in the sample:
1.04 g - 0.61 g = 0.43 g
Divide by the molar mass of water: 18.01 g / mol to obtain the number of moles of water:
0.43 g / 18.01 g / mol = 0.0239 moles
Calculate the number of moles of dehydrated NiSO4
Number of moles = mass in grams / molar mass
molar mass of NiSO4 = 154.75 g/mol
number of moles NiSO4 = 0.61 g / 154.75 g/mol = 0.00394 moles
Now determine the molar ratio water to NiSO4: 0.0239 / 0.00394 = 6.07 ≈ 6
Then, the formula of the hydrate product is NiSO4 · 6 H2O.
Use the prefix hexa (6) to name the compound: Nickel(II) sulfate hexadydrate
Answer:
NaH one atom of sodium react with one hydrogen to form sodium hydride
Explanation:
Answer:
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Answer:
Sodium oxide reacts exothermically with cold water to produce sodium hydroxide solution. A concentrated solution of sodium oxide in water will have pH 14. ... For example, it reacts with dilute hydrochloric acid to produce sodium chloride solution.
Answer:
0.196 M
Explanation:
First, we have to calculate the moles of sodium hydroxide.
moles = mass / molar mass
moles = 3.9280 g / (39.997 g/mol) = 0.098207 mol
It is important to realize that even though 300 mL is the volume of water firstly added to dissolve the hydroxide, the flask is then filled to the mark, meaning that the volume of the solution is 500 mL = 0.500 L.
The molar concentration of sodium hydroxide is:
The concentration is an intensive property, that is, it does not depend on the amount of matter. As a consequence, the concentration of the 50 mL of solution in the buret is the same as the concentration in the flask.