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Naily [24]
2 years ago
13

In the titration of 50. 0 mL of 0. 400 M HCOOH with 0. 150 M LiOH, how many mL of LiOH are required to reach the equivalence poi

nt
Chemistry
1 answer:
mart [117]2 years ago
8 0

The volume of the 0.15 M LiOH solution required to react with 50 mL of 0.4 M HCOOH to the equivalence point is 133.3 mL

<h3>Balanced equation </h3>

HCOOH + LiOH —> HCOOLi + H₂O

From the balanced equation above,

The mole ratio of the acid, HCOOH (nA) = 1

The mole ratio of the base, LiOH (nB) = 1

<h3>How to determine the volume of LiOH </h3>
  • Molarity of acid, HCOOH (Ma) = 0.4 M
  • Volume of acid, HCOOH (Va) = 50 mL
  • Molarity of base, LiOH (Mb) = 0.15 M
  • Volume of base, LiOH (Vb) =?

MaVa / MbVb = nA / nB

(0.4 × 50) / (0.15 × Vb) = 1

20 / (0.15 × Vb) = 1

Cross multiply

0.15 × Vb = 20

Divide both side by 0.15

Vb = 20 / 0.15

Vb = 133.3 mL

Thus, the volume of the LiOH solution needed is 133.3 mL

Learn more about titration:

brainly.com/question/14356286

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Help! I need help on how to do these problems.
svetlana [45]

Answer:

a. 3; b. 5; c. 10; d. 12

Explanation:

pH is defined as the negative log of the hydronium concentration:

pH = -log[H₃O⁺] (hydronium concentration)

For problems a. and b., HCl and HNO₃ are strong acids. This means that all of the HCl and HNO₃ would ionize, producing hydronium (H₃O⁺) and the conjugate bases Cl⁻ and NO₃⁻ respectively. Further, since all of the strong acid ionizes, 1 x 10⁻³ M H₃O⁺ would be produced for a., and 1.0 x 10⁻⁵ M H₃O⁺ for b. Plugging in your calculator -log[1 x 10⁻³] and -log[1.0 x 10⁻⁵] would equal 3 and 5, respectively.

For problems c. and d. we are given a strong base rather than acid. In this case, we can calculate the pOH:

pOH = -log[OH⁻] (hydroxide concentration)

Strong bases similarly ionize to completion, producing [OH⁻] in the process; 1 x 10⁻⁴ M OH⁻ will be produced for c., and 1.0 x 10⁻² M OH⁻ produced for d. Taking the negative log of the hydroxide concentrations would yield a pOH of 4 for c. and a pOH of 2 for d.

Finally, to find the pH of c. and d., we can take the pOH and subtract it from 14, giving us 10 for c. and 12 for d.

(Subtracting from 14 is assuming we are at 25°C; 14, the sum of pH and pOH, changes at different temperatures.)

6 0
3 years ago
How many grams of CH4 will be in a 500ml contain at STP?
ArbitrLikvidat [17]

Answer:

Mass = 0.32 g

Explanation:

Given data:

Mass of CH₄ = ?

Volume of CH₄ = 500 mL (500 mL× 1L/1000 mL= 0.5 L)

Temperature = 273 K

Pressure = 1 atm

Solution:

Volume of CH₄:

500 mL (500 mL× 1L/1000 mL= 0.5 L)

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

By putting values,

1 atm× 0.5 L = n×0.0821 atm.L/ mol.K  × 273 K

0.5 atm.L = n×22.4 atm.L/ mol

n = 0.5 atm.L / 22.4 atm.L/ mol

n = 0.02 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 0.02 mol × 16 g/mol

Mass = 0.32 g

7 0
3 years ago
What are the three main technical support options for Microsoft users? Find It Myself, Ask the Community, Get Live Help Communit
Katen [24]

Answer:

Find It Myself, Ask the Community, Get Live Help

Explanation:

The three main options for Microsoft users are Find It Myself, Ask the Community, Get Live Help. The first of which is finding it yourself through the search menu or help guidelines provided by Microsoft in all of their operating systems. Secondly, would be asking the community through search engines such as Google or through Microsoft help forums. Lastly, would be getting live help since Microsoft opertaing systems have a remote desktop feature that allows you to connect to another IT professional from a distance, or you can simply contact an IT professional to visit you in person for technical assistance.

8 0
3 years ago
Determine the number of atom in 5.0 moles in SI
Alex

Answer: 3.01 x 10^24 atoms

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms

So, 1 mole of SI = 6.02 x 10^23 atoms

5.0 moles = Z atoms

To get the value of Z, cross multiply:

(Z atoms x 1 mole) = (6.02 x 10^23 atoms x 5.0 moles)

Z atoms•1 mole = 30.1 x 10^23 atoms•moles

Divide both sides by 1 mole

Z atoms•1 mole / 1 mole = 30.1 x 10^23 atoms•moles / 1 mole

Z = 30.1 x 10^23 atoms

[Place Z in standard form

So, Z = 3.01 x 10^24 atoms]

Thus, there are 3.01 x 10^24 atoms in 5.0 moles in SI

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When Na2O is mixed with Mn(NO3)4 it forms NaNO3 and MnO2. We start with 25.0 g
coldgirl [10]
I don’t know what have you heard that with na20
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