In the titration of 50. 0 mL of 0. 400 M HCOOH with 0. 150 M LiOH, how many mL of LiOH are required to reach the equivalence poi
1 answer:
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Answer: 2800 g
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number of particles.
Given mass = 5 kg = 5000 g
1 mole of produces = 1 mole of
50 moles of produces =
of
Mass of
2800 g of is produced from 5.0 kg of limestone.