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svp [43]
3 years ago
13

Oxidation-reduction reactions occur because of the competition between particles for

Chemistry
1 answer:
Scorpion4ik [409]3 years ago
5 0
Answer:
            <span>Oxidation-reduction reactions occur because of the competition between particles for <u>Electrons</u>.

Explanation:
                   Oxidation is defined as the loss of electrons. While, Reduction is defined as the gain of electrons. We also know that oxidation and reduction reaction happens simultaneously. Therefore, the electrons lost by one element are gained by another element.

Example:
                                  2 Fe  +  O</span>₂     →      2 FeO

In above reaction the competition for electrons is found between Oxygen and Iron. 

Oxidation of Iron:
             
                                     2  Fe     →     2 Fe²⁺  +  4 e⁻

Reduction of Oxygen:

                                     O₂  +  4 e⁻     →     2 O²⁻

Hence, in above reaction oxygen wins the competition by gaining the electrons from Iron.
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6 0
3 years ago
What is the molar concentration of 250. mL of aqueous solution containing 48.8 g of glucose, C6H12O6?
Nezavi [6.7K]

Answer:

1.08 mol/L

Explanation:

Molarity -

Molarity of a substance , is the number of moles present in a liter of solution .

M=\frac{n}{V}

M = molarity ( unit = mol / L or M )

V = volume of solution in liter ( unit = L ),  

n = moles of solute ( unit = mol ),  

Moles is denoted by given mass divided by the molecular mass ,  

Hence ,

n=\frac{w}{m}

n = moles ,

w = given mass ,

m = molecular mass .

From the information of the question ,

V = 250 mL

Since ,

1 mL = 1/1000L

V = 0.250 L

w = 48.8 g

As we known , the mass of glucose ,

m = 180g/mol ,

From the above formula , moles is given as ,

n=\frac{w}{m}

substituting the corresponding values ,  

n = 48.8g / 180g/mol

n = 0.27 mol

Now , the molarity can be calculated by using the above equation ,

M = n / V

substituting the corresponding values ,  

M = 0.27 mol /  0.250 L

M = 1.08 mol/L

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