15 electricians worked for 24 days to the whole job, now, there are 15 of them, so on any given day, each electrician worked one whole day, in 24 days, that one electrician worked 24 days total.
now, there were 15 electricians on any given day though, since each one of them worked the whole day that one day, so the "days work worth" on a day is 15, so the house gets 15days worth of work because of that.
so how many "days worth" did all 15 do on the 24 days, well, 15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15, namely 15 * 24, or 360 days worth of work.
since it takes 360 days worth of work to do the whole wiring, in how many days would 18 electricians do it? 360/18.
I am guessing it is b! because BG and BA are sides, and BAU and BGN are angles.
(i) the number of students who passed in the first and in the second division
76+95=171 students
(ii) The ratio of the number of students who passed in the first second and in the third division.
RATIO is 4:5:(25/19) or 4:5: 1.3157894…….
225-29=196 (29students failed)
196-25=171. (Subtract 25 students from the 3rd division)
4x+5x= 171 (171 students from 1st and second division)
9x=171
X=19
4x19=76 5x19= 95 1.31578.....x19= 25
Answer:
I cant really see any answer but if I had to simplify, then the answer would be 2t - 8 + 1, which would then be simplified to 2t - 7.
Have a nice and wonderfull day.
Brainliest would be appreciated.
Step-by-step explanation:
