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gladu [14]
4 years ago
5

How many solutions are possible for a system of equations containing exactly one linear and one quadratic equation?

Mathematics
1 answer:
olganol [36]4 years ago
4 0
There can be as many as 2 solutions.
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Finally, put in everything we've found to finish the equation.
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Help on math homework
vredina [299]
 y=ax+b     and  y=cx+d,  these lines are parallels if  a = c 
2) a) y = 3x+9, the two lines are y = 3x-4 and y = 3x+5
<span>b) y = -5x+6, the two lines are y = -5x+4 and y = -5x-2
</span>c) y = -7x+8, the two lines are y = -7x-9 and y = <span>-7x+7
same method with the d e and f

3) </span><span>y=ax+b     and  y=cx+d,  these lines are perpendicular  if  a x c=-1
a) y=3x+7, the two lines are y= (-1/3 )x +2, and y= (-1/3)x-6  </span><span>
b)  </span>y= -5/6x-2, the two lines are y= (6/5)x -2, and y= (6/5)x+13<span>
c)  </span>y= - 5x+8, the two lines are y= (1/5)x - 32, and y= (<span>1/5 )x+11 
the same method for d e and f

4) coordinates of the midpoints 
a)   (0, 0) and (5, 15)
the midpoints is  ((0+5) / 2,  (0+15)/2)= (5/2, 15/2)
b)   (2, 4) and (6, -5) 
</span><span>the midpoints is  ((2+6) / 2,  (4-5)/2)= (4, -1/2)
</span>c)  (3,5) and (7,5)
<span>the midpoints is  ((3+7) / 2,  (5+5)/2)= (5, 5)
</span>the same method for d e and f
6 0
3 years ago
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