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gladu [14]
3 years ago
5

How many solutions are possible for a system of equations containing exactly one linear and one quadratic equation?

Mathematics
1 answer:
olganol [36]3 years ago
4 0
There can be as many as 2 solutions.
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Here is the answer to ur question :) Hope this helps!

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A walking path across a park is represented by the equation y=-3x - 3. A
luda_lava [24]

Answer:

y = (1/3)x + 7

Step-by-step explanation:

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y = mx + b

In this form, "m" represents the slope and "b" represents the y-intercept.

The slope of a perpendicular line is the opposite-signed, reciprocal of the original line's slope. Therefore, if the slope of the original line is m = -3, the new slope is m = 1/3.

The y-intercept can be found by plugging the new slope and the values from the point (-3, 6) into the slope-intercept form equation.

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y = mx + b                                  <----- Slope-intercept form

6 = (-3)(1/3) + b                           <----- Insert values

6 = -1 + b                                    <----- Multiply -3 and 1/3

7 = b                                           <----- Add 1 to both sides

Now, that you have the slope and y-intercept, you can construct the equation of the perpendicular line.

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zavuch27 [327]

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(-5/8, 27/20) is the answer.

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