Question

Cameron used 1 3/4 ounces of hydrochloric acid in one experiment. She used 2 1/8 ounces of the acid in a second experiment. How much more acid did Cameron use in the second experiment?

Answer 1

Answer:

Amount required is $x=\frac{3}{8}$

Step-by-step explanation:

Given : Cameron used $1\frac{3}{4}$ ounces of hydrochloric acid in one experiment. She used $2\frac{1}{8}$ ounces of the acid in a second experiment.

To find : How much more acid did Cameron use in the second experiment?

Solution :

In one experiment,

Cameron used $1\frac{3}{4}$ ounces of hydrochloric acid

i.e $1\frac{3}{4}=\frac{7}{4}$

In second experiment,

She used $2\frac{1}{8}$ ounces of the acid.

i.e. $2\frac{1}{8}=\frac{17}{8}$

Let x amount more she used then experiment 1 in experiment 2.

So, the equation became

$\frac{7}{4}+x=\frac{17}{8}$

$x=\frac{17}{8}-\frac{7}{4}$

$x=\frac{17-14}{8}$

$x=\frac{3}{8}$

Therefore, Amount required is $x=\frac{3}{8}$

Answer 2

3/8ths more
2 1/8 -1 3/4 =
17/8 - 14/8 = 3/8ths