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2 years ago

1. Why does cabbage juice have different colors at different pH levels?

1 answer:

7 0

1:Red cabbage contains a water-soluble pigment called anthocyanin that changes color when it is mixed with an acid or a base.

2: Basic

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What is the percent of hydrogen peroxide in the solution when 5.02g of H2O2 solution reacts to produce 0.153g of H2O2? 2H2O2 (l)

Murljashka [212]

Given:

Mass of H2O2 solution = 5.02 g

Mass of H2O2 = 0.153 g

To determine:

The % H2O2 in solution

Explanation:

Chemical reaction-

2H2O2(l) → 2H2O(l) + O2(g)

Mass % of a substance in a solution = (Mass of the substance/Mass of solution) * 100

In this case

% H2O2 = (Mass H2O2/Mass of solution)* 100 = (0.153/5.02)*100 = 3.05%

Ans: % H2O2 in the solution = 3.05%

5 0

3 years ago

DOES ANYONE TAKE ANATOMY AND PHYSIOLOGY I WILL PAY FOR HELPPP!!!!!

lisabon 2012 [21]

Answer:

I take Anatomy and Physiology. Tell me if I can help.

7 0

3 years ago

A material has an ASTM grain size number of 7. Determine the magnification, if the number of grains per square inch observed is:

Luden [163]

Answer:

A) M = 100X

B) M = 36X

C) M = 178.88X

Explanation:

Given data:

ASTM grain size number 7

a) total grain per inch^2 - 64 grain/inch^2

we know that number of grain per square inch is given as

$Nm = 2^{n-1} (\frac{100}{M})^2$

where M is magnification, n is grain size

therefore we have

$64 = 2^{7-1}(\frac{100}{M})^2$

solving for M we get

M = 100 X

B) total grain per inch^2 = 500 grain/inch^2

we know that number of grain per square inch is given as

$Nm = 2^{n-1} (\frac{100}{M})^2$

where M is magnification, n is grain size

therefore we have $500 = 2^{7-1}(\frac{100}{M})^2$

solving for M we get

M = 36 X

C) Total grain per inch^2 = 20 grain/inch^2

we know that number of grain per square inch is given as

$Nm = 2^{n-1} (\frac{100}{M})^2$

where M is magnification, n is grain size

therefore we have $20 = 2^{7-1}(\frac{100}{M})^2$

solving for M we get

M = 178.88 X

8 0

3 years ago

calculate the mass of butane needed to produce 64.1 g of carbon dioxide to three significant figures and appropriate units

cricket20 [7]

Answer:

21.2 gm

Explanation:

calculate the mass of butane needed to produce 64.1 g of carbon dioxide to three significant figures and appropriate units

butane is the hydrocarbon C4H10

in combustion, we react hydrocarbons with O2 to form CO2 and H2O

C4H10 + O2----------------> CO2 + H2O

BALANCE

2C4H10 + 1302--------> 8CO2 + 10 H2O

the molar mass of CO2 is 12 + 16X2 = 44

64.1 gm of CO2 is

64.1/44 = 1.46 MOLES OF CO2,

FOR EVERY 8 MOLES OF CO2 WE NEED 2 MOLES OF BUTANE IT IS A

8:2 OR 4:1 RATIO. THE MOLES OF C4H10 ARE 1/4 THE MOLES OF CO2

THE MOLES OF C4H10 H10 ARE 1.46/4 =0.365 MOLES

THE MOLAR MASS OF BUTANE IS 58.12

0.365 MOLES OF C4H10 HAS A MASS OF 0.365 X 58.12 = 21.2 gm

6 0

3 years ago

Find the pH of a solution whose H+ concentration is 1.8 x 10-12

frutty [35]

Answer:

11.74

Explanation:

The formula to find the pH of a solution is..

pH = -log [H⁺]

pH = -log [1.8×10¹²]

pH = 11.74

The answer would be to 2 decimal places because the concentration is two significant digits.

8 0

3 years ago