All categories

3 years ago

What happens when water is added to quicklime? Write two observations.

Chemistry

1 answer:

Neporo4naja [7]3 years ago

3 0

Answer:

1.Most metal oxides are insoluble in water but some of these (e.g. Na2O.

Explanation:

2.: (i) A hissing sound is observed.

1.ii) The mixture starts boiling and lime water is obtained.

You might be interested in

How many moles are equal to 3.0x10^23 atoms of germanium? PLS ANSWER WITH WORK!

horrorfan [7]

1 mole=6.02 x 10^23 atoms so how many moles are there in 3.0 x 10^23 we will cross multiply, 1 x 3.0 x 10^23 / 6.02 x 10 ^23. Which will give us 0.498 moles.
Hope this helped

6 0

3 years ago

The expression of the theoretical yield (TY) in function of limiting reagent (LR) of a reaction is as follows: TY = ideal mole r

spin [16.1K]

Answer: The theoretical yield of acetanilide is 6.5 grams.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For aniline:

Given mass of aniline = $4.50\times 10^0=4.50g$ (We know that: $10^0=1$ )

Molar mass of aniline = 93.13 g/mol

Putting values in equation 1, we get:

$\text{Moles of aniline}=\frac{4.50g}{93.13g/mol}=0.048mol$

For acetic anhydride:

To calculate the mass of acetic anhydride, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Volume of acetic anhydride = $(1.25\times \text{Mass of aniline})=1.25\times 4.50=5.625mL$

Density of acetic anhydride = 1.08 g/mL

Putting values in above equation:

$1.08g/mL=\frac{\text{Mass of acetic anhydride}}{5.625mL}\\\\\text{Mass of acetic anhydride}=(1.08g/mL\times 5.625mL)=6.08g$

Given mass of acetic anhydride = 6.08 g

Molar mass of acetic anhydride = 102.1 g/mol

Putting values in equation 1, we get:

$\text{Moles of acetic anhydride}=\frac{6.08g}{102.1g/mol}=0.06mol$

The chemical equation for the reaction of aniline and acetic anhydride follows:

$C_6H_5NH_2+CH_3COOCOCH_3\rightarrow C_6H_5NHCOCH_3+CH_3COOH$

By Stoichiometry of the reaction:

1 mole of aniline reacts with 1 mole of acetic anhydride

So, 0.048 moles of aniline will react with = $\frac{1}{1}\times 0.048=0.048mol$ of acetic anhydride

As, given amount of acetic anhydride is more than the required amount. So, it is considered as an excess reagent.

Thus, aniline is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of aniline produces 1 mole of acetanilide

So, 0.048 moles of aniline will produce = $\frac{1}{1}\times 0.048=0.048mol$ of acetanilide

Now, calculating the theoretical yield of acetanilide by using equation 1:

Moles of acetanilide = 0.048 moles

Molar mass of acetanilide = 135.17 g/mol

Putting values in equation 1, we get:

$0.048mol=\frac{\text{Mass of acetanilide}}{135.17g/mol}\\\\\text{Mass of acetanilide}=(0.048mol\times 135.17g/mol)=6.5g$

Hence, the theoretical yield of acetanilide is 6.5 grams.

3 0

3 years ago

Can endothermic chemical reactions be spontaneous?

Verdich [7]

Yes, IF entropy is high enough

5 0

3 years ago

The male monster has an HH genotype, and the female has a hh genotype. Will the baby monsters have horns?

viva [34]

Answer:

like the others its C

Explanation:

the dad has horns but the mom does not so the babys could or they could not

8 0

2 years ago

Read 2 more answers

In yeast, ethanol is produced from glucose under anaerobic conditions. A cell‑free yeast extract is placed in a solution that co

nadezda [96]

Answer:

0.35 milli moles of ethanol can be theoretically be produced under these conditions.

Explanation:

$C_6H_{12}O_6 + 2 ADP + 2 Pi\rightarrow 2 C_2H_5OH + 2 ATP + 2 CO_2$

Moles of glucose = $3.50\times 10^2$ milli mole

Moles of ADP = 0.35 milli mole

Moles of Pi = 0.35 milli mole

Moles of ATP = 0.70 milli mole

As we can see that ADP and Pi are in limiting amount which means tat they are limiting reagent. So, the moles of ethanol produced will depend upon the moles of ADP and Pi.

According to reaction, 2 moles of ADP gives 2 moles of glucose.

Then 0.35 milli moles of ADp will give :

$\frac{2}{2}\times 0.35 mmol=0.35 mmol$ of ethanol

0.35 milli moles of ethanol can be theoretically be produced under these conditions.

5 0

3 years ago