Answer:
Hi
A conjugate acid is a chemical compound formed by the reception of a proton by a base; therefore, it is a base with an added hydrogen ion. On the other hand, a conjugate base is what remains after an acid has donated its proton during a chemical reaction, so it can be said that a conjugate base is a species modified by extracting a proton from an acid.
In pyrrole, the electron pair can be relocated to the ring and its availability is very small. In addition, the concept of aromaticity comes into play.
In the attached file are the schemas of the conjugate bases.
Explanation:
In case of a shortage in petroleum and natural gas, a company should find a way to make nylon without using natural resources.
Nylon is a very important material used in numerous applications. As a result of this, the demand for nylon as a raw material has genuinely been on the high side ever since.
However, nylon production depends on petroleum and natural gas. It is possible that there could be a shortage of these resources since they are obtained from the environment. In such cases, a company should find a way to make nylon without using natural resources.
Learn more about polymers: brainly.com/question/17555341
Explanation:
<em>Hi</em><em> </em><em>there</em><em>!</em><em>!</em>
<em>you</em><em> </em><em>asked</em><em> </em><em>to</em><em> </em><em>multiply</em><em> </em><em>these</em><em> </em><em>all</em><em> </em><em>right</em><em>,</em>
<em>you</em><em> </em><em>can</em><em> </em><em>simply</em><em> </em><em>multiply</em><em> </em><em>it</em><em> </em><em>,</em>
<em>=</em><em>3</em><em>cm</em><em> </em><em>×</em><em> </em><em>4</em><em> </em><em>cm</em><em> </em><em>×</em><em> </em><em>1</em><em>cm</em>
<em>=</em><em> </em><em>1</em><em>2</em><em>cm</em><em>^</em><em>2</em><em>×</em><em>1</em><em>cm</em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>4</em><em>×</em><em>3</em><em>=</em><em>1</em><em>2</em><em>)</em>
<em>=</em><em> </em><em>1</em><em>2</em><em>cm</em><em>^</em><em>3</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>1</em><em>2</em><em>×</em><em>1</em><em>=</em><em>1</em><em>2</em><em>)</em>
<em>Therefore</em><em>, </em><em> </em><em>the</em><em>answer is</em><em> </em><em>1</em><em>2</em><em> </em><em>cm</em><em>^</em><em>3</em><em>.</em>
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>
<span>The answer is true that Group 1A elements (except for hydrogen) are the
alkali metals. Groups 2A are alkaline earth metals. Group 3B-12B are transition
metals. Group 3A to 4A except Boron, Carbon, Nitrogen, oxygen, silicon,
phosphorus, sulfur, germanium, astatine, selenium, antimony, tellurium, polonium
are basic metal. Carbon, nitrogen, oxygen, phosphorus, sulfur and selenium are
nonmetals. Boron, silicon, germanium, astatine, antimony, tellurium and polonium
are metalloids. Groups 7A are halogens. Groups 8A are noble gases. The lower
part of the periodic table are lanthanides and actinides.</span>
Given the reaction 2Pb(s)+O2(g)= 2PbO(s) and a reactant amount of 451.4 grams, we are asked for the yield of the reaction. The amount of lead present produces 451.4/207.2 *( 2/2) *(223.2) via 100% conversion, 486.26 grams lead (II) oxide. hence the percent yield is 356.7g /<span>486.26 g or equal to 73.35 percent</span>