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goldenfox [79]
4 years ago
15

If you are told that one of them is Cr2O3 and the other is OsO4, which one do you expect to be the yellow solid?

Chemistry
2 answers:
Katen [24]4 years ago
7 0
From own experience, I know that OsO4 is colorless, but Cr2O3 is actually a solid green from what I have seen. but I guess it could appear yellow-greenish.
luda_lava [24]4 years ago
4 0

Answer is: OsO₄ (osmium tetroxide or osmium(VIII) oxide).

Osmium(VIII) is colourless, but most samples appear yellow, because of the presence of the impurity OsO₂ (osmium(IV) oxide), which is yellow-brown in colour.

Cr₂O₃ (chromium(III) oxide) is light to dark green compound. It is used as a pigment. In this chemical compound chromium has oxidation number +3.

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7 0
4 years ago
Read 2 more answers
Mean, median and mode are best described as which?
Nonamiya [84]

Answer:

B. Measures of central tendency

Explanation:

Mean, median and mode are best described as measures of central tendency of a given data set.

Mean is the average of the samples given

Mode is the data point with the most frequent occurrence

Median is the data point that lies in the middle

  • All these parameters tells us how far a data point is from the middle or how close they are.
5 0
3 years ago
How much heat, in calories, is needed to raise the temperature of 125.0 g of Lead (c lead = 0.130 J/g°C) from 17.5°C to 41.1°C?
pav-90 [236]
95.6 cal
are needed.
Explanation:
Use the following equation:
q
=
m
c
Δ
T
,
where:
q
is heat energy,
m
is mass,
c
is specific heat capacity, and
Δ
T
is the change in temperature.
Δ
T
=
T
final
−
T
initial
Known
m
=
125 g
c
Pb
=
0.130
J
g
⋅
∘
C
T
initial
=
17.5
∘
C
T
final
=
42.1
∘
C
Δ
T
=
42.1
∘
C
−
17.5
∘
C
=
24.6
∘
C
Unknown
q
Solution
Plug the known values into the equation and solve.
q
=
(
125
g
)
×
(
0.130
J
g
⋅
∘
C
)
×
(
24.6
∘
C
)
=
400. J

(rounded to three significant figures)
Convert Joules to calories
1 J
=
0.2389 cal
to four significant figures.
400
.
J
×
0.2389
cal
1
J
=
95.6 cal

(rounded to three significant figures)
95.6 cal
are needed.
8 0
3 years ago
The concentration of gallium in silicon is 5.0 × 10−7 at%. What is the concentration in kilograms of gallium per cubic meter?
Step2247 [10]

Answer:

[ Ga ] = 1.163 E-8 Kg/m³

Explanation:

  • %wt = [(mass Ga)/(mass Si)]*100 = 5.0 E-7 %

⇒ 5.0 E-9 = m Ga/m Si

assuming: m Si = 100 g = 0.1 Kg

⇒ m Ga = (5.0 E-9)*(0.1 Kg) = 5 E-10 Kg

∴ density (δ) Si = 2.33 Kg/m³

⇒ Volume Si = (0.1 Kg)*(m³/2.33 Kg) = 0.043 m³

⇒ [ Ga ] = (5 E-10 Kg)/(0.043 m³) = 1.163 E-8 Kg/m³

⇒ [ Ga ] =

3 0
3 years ago
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