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3 years ago

PLEASE HELP GUYS HURRY

Mathematics

1 answer:

julia-pushkina [17]3 years ago

7 0

411 is the total amount of shells he would use

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–5x+8y= 10<br> 7x-2y= -14

Lostsunrise [7]

Answer:

x=2,y=0

(You did not provide enough information for me to know what to do with said equations, so I'm assuming it was System of Equations.)

7 0

3 years ago

Geometry help help help

Kruka [31]

BD = AC/2
4x+2 = (5x+13)/2

2(4x+2) = 5x+13
8x + 4 = 5x+13
8x - 5x = 13 -4
3x = 9
x = 3

8 0

3 years ago

The size of a TV is measured by its diagonal. You want to buy a TV that has a 32

ANEK [815]

The width of the TV is 27.9 inches

Step-by-step explanation:

Given,

Diagonal of TV = 32 inch

Height of TV = 15.7 inch

The diagonal makes the TV into a right triangle,

Therefore,

Diagonal = hypotenuse = c = 32 inch

Height = perpendicular = a = 15.7 inch

Width = base = b

Using pythagoras theorem

$a^2+b^2=c^2\\(15.7)^2+b^2=(32)^2\\246.49+b^2=1024\\b^2=1024-246.49\\b^2=777.51$

Taking square root on both sides

$\sqrt{b^2}=\sqrt{777.51}\\b=27.88$

Rounding off to nearest tenth

b = 27.9 inches

The width of the TV is 27.9 inches

Keywords: Pythagoras theorem, square root

Learn more about square root at:

#LearnwithBrainly

7 0

3 years ago

2 cars are 700 miles apart. They travel toward each other. One of the cars travels at 75mph, the other travels at 100 mph. How l

olga2289 [7]

Answer: C 4

Step-by-step explanation:

Use the formula: distance = rate x time

We can say that train 1 travels a distance of x, and train 2 travels a distance of 700 - x

The rate of train 1 is 75 mph, and the rate of train 2 is 100 mph

The time traveled for the two trains will be the same. We can represent that with the variable t.

We have the following equation for train 1:

x = 75t

For train 2, we have this equation:

700 - x = 100t

Use the Substitution Method by replacing x in the equation for train 2 with the value 75t.

700 - 75t = 100t

700 = 175t

700/175 = 4 hours.

It will take 4 hours for the two trains to meet.

6 0

3 years ago

Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting

stealth61 [152]

Answer:

Anna's walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$ and refer attachment.

Step-by-step explanation:

Let the origin be the point 1 from where Ann start walking.

Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,

Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)

Ann walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$

Thus, Anna's walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$

7 0

3 years ago

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