14+10y > 3(y+14)
14+10y > 3y + 42
-3y -3Y
14 + 10y - 3y < 42
-14 -14
10y - 3y >42 - 14
7y > 28
Y> 4
The list of choices you included doesn't have any correct expressions on it.
-- If the rocket went straight up, and then dropped back at the same place
it was launched from, then it must have dropped straight down.
-- The route it followed on the way down was exactly the same as the
route it followed on the way up.
-- Since it reached a maximum height of 150-ft from the ground
and the route was straight, the length of the route was 150-ft.
-- (150-ft going up) plus (150-ft coming down) = 300-ft traveled all together.
Answer:
a. Linear
A linear line is straight.
Answer:
Uhhh try downloading.... Conects... ¯\_(ツ)_/¯
Step-by-step explanation:
....*whispers* Your welcome....
Answer:
Step-by-step explanation:
compare with that y=mx+c
where m=slope .
So after comparing we get m=
As the lines are perpendicular
therefore m2=
Now from the equation
this equation passing to the point (-5,5) with m=
Therefore equation is
