All categories

3 years ago

X+(-3)=-7 Solve the equation and enter the value of x below

Mathematics

2 answers:

shutvik [7]3 years ago

5 0

Answer:

$x = -4$

Step-by-step explanation:

<u>Step 1: Add 3 to both sides </u>

$x + (-3) = -7$

$x - 3 + 3 = -7 + 3$

$x = -4$

Answer: $x = -4$

Phoenix [80]3 years ago

3 0

Answer:

x=-4

Step-by-step explanation:

x+(-3)=-7

x-3=-7

x=-7+3=3-7

x=-4

You might be interested in

Find the surface area of the prism.

KonstantinChe [14]

C. 94 m^2 is the surface area

6 0

4 years ago

Antiderivative of Acceleration is???

Effectus [21]

Answer:

Since acceleration is the derivative of velocity, velocity is the antiderivative of acceleration. If you know the acceleration for all time, and if you know the starting velocity, you can figure out the velocity for all time.

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

An investment website can tell what devices are used to access the site. The site managers wonder whether they should enhance th

AveGali [126]

Answer:

0.8418

Step-by-step explanation:

We have p = 0.36

Sample size = 200

We have to find the standard error of proportion

= √p(1-p)/n

= √0.36(1-0.36)/200

= 0.034

P(0.30<p^0.40)

= 0.30-0.36/0.034 = -1.76,

0.40-0.36/0.034 = 1.18

P(-1.76<z<1.18)

When we go to the standard normal distribution table

P(z<1.18) = 0.8810

P(z<-1.76) = 0.0392

0.8810 - 0.0392

= 0.8418

This is the probability of the sample proportion being between 0.30 and 0.40

3 0

3 years ago

If anyone know, please help thanks!

alexira [117]

Just take 43 and subtract 7 to get 36

If you check, "7 more than 36" does equal 43

So 36

7 0

3 years ago

Read 2 more answers

The annual net income of a company for the period 2007–2011 could be approximated by P(t) = 1.6t2 − 11t + 44 billion dollars (2

son4ous [18]

Answer:

$P'(t) = 3.2 t -11$

And we can set equal this derivate to 0 in order to find the critical point and we got:

$3.2 t-11= 0$

$t = \frac{11}{3.2}= 3.4375$

And we can calculate the second derivate and we got:

$P''(t) = 3.2 >0$

So then w can conclude that the value of t = 3.4375 represent the minimum value for the function and we can replace in the original function and we got:

$P(3.4375) = 1.6(3.4375)^2 - (11*3.4375) +44 = 25.094$

So then the minimum annual income occurs at t = 3.43 (between 2008 and 2009) and the value is 25.094

Step-by-step explanation:

For this case we have the following function:

$P(t) = 1.6 t^2 -11t +44$

Where P represent the annual net income for the period 2007-2011 and $2 \leq t \leq 7$

And t represent the time in years since the start of 2005

In order to find the lowet income we need to use the derivate, given by:

$P'(t) = 3.2 t -11$

And we can set equal this derivate to 0 in order to find the critical point and we got:

$3.2 t-11= 0$

$t = \frac{11}{3.2}= 3.4375$

And we can calculate the second derivate and we got:

$P''(t) = 3.2 >0$

So then w can conclude that the value of t = 3.4375 represent the minimum value for the function and we can replace in the original function and we got:

$P(3.4375) = 1.6(3.4375)^2 - (11*3.4375) +44 = 25.094$

So then the minimum annual income occurs at t = 3.43 (between 2008 and 2009) and the value is 25.094

5 0

3 years ago