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Galina-37 [17]
4 years ago
15

How Many grams Dissolve at 10

Chemistry
2 answers:
Fittoniya [83]4 years ago
7 0
Correct answer is b

slamgirl [31]4 years ago
6 0

Answer:

b. 9 g

Explanation:

Solubility Ce2(SO4)3 at 10°C is a little less than 10 g/100 g water.

So, the best answer is b. 9 g.

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Which formula represents Carbonic acid
Degger [83]

Answer:

H2CO3 represents carbonic acid

8 0
3 years ago
Which statement describes a reaction at 298 K if AH = 31 kJ/mol, AS = 0.093
melisa1 [442]

Answer: (D) it is not spontaneous.

6 0
3 years ago
Sodium phosphate dissolves as follows: na3po4(s) → 3na (aq) po4-(aq). How many moles of na3po4 are required to make 1. 0 l of so
bezimeni [28]

The 0.05 moles of Na_{3}PO_{4} required to make 1 L of solution in which the Na concentration is 0. 15 M.

Calculation,

The Sodium phosphate dissolves as follows:

Na_{3}PO_{4}(s) → 3Na^{+} (aq)+PO_{4}^{-} (aq)

To make 1. L of solution in which the  Na^{+concentration is 0. 15 M

The morality  of Na^{+= 0.15 M = number of moles / volume in lit

The morality of Na^{+= 0.15 M = number of moles /1 Lit

number of moles of Na^{+ = 0.15 mole

The mole ratio is 1: 3

It means, the 1 mole of Na_{3}PO_{4}(s) required to form 3 mole of Na^{+

So, to form 0.15 mole of Na^{+  = 1×0.15 / 3 moles of Na_{3}PO_{4}(s)required.

Hence, number of moles of Na_{3}PO_{4}(s) required = 0.05 moles.

learn about moles

brainly.com/question/26416088

#SPJ4

6 0
2 years ago
An unknown metal sample has a mass : of 11.29. and a volume of 2 cm3. What is the : density of the unknown metal? ​
tatuchka [14]

Answer:

\boxed{\sf Density \ of \ the \ unknown \ metal = 5.645 \ g/cm^3}

Given:

Mass = 11.29 g

Volume = 2 cm³

To Find:

Density of unknown metal

Explanation:

Formula:

\boxed{ \bold{Density = \frac{Mass}{Volume}}}

Substituting value of mass & volume in the formula:

\sf \implies Density =  \frac{11.29}{2} \\  \\   \sf \implies Density =  5.645 \: g/cm^3

3 0
3 years ago
Hi ndzjfndzlkfmaspodje-sapd
Setler [38]

Answer:

hey

Explanation:

5 0
3 years ago
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