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larisa86 [58]
3 years ago
15

Which of the following represents a propagation step in the monochlorination of methylene chloride (CH2Cl2)?a. CHCl3 + Cl. Right

arrow .CCl3 + HCl.b. CHCl2 + Cl2 right arrow CHCl3 + Cl..c. CH2Cl + Cl2 right arrow CH2Cl2 + Cl..d. CHCl2 + Cl. Right arrow CHCl3

Chemistry
1 answer:
svetlana [45]3 years ago
3 0

Answer:

B = CHCl2 + Cl2 --> CHCl3 + Cl

Explanation:

Free radical halogenation is a chlorination reaction on Alkane hydrocarbons. This involves the splitting of molecules into radicals/ unstable molecules in the presence of sunlight/ U.V light which ensures bonding of the molecules.

Free radical chlorination is divided into 3 steps which are:

The initiation step

The propagation step

The termination step

So in reference to the question, propagation step involves two steps.

The first step is where the molecule in this case the methylene chloride(CH2Cl2) loses a hydrogen atom and then bond with a chlorine atom radical to give a nethylwnw chloride radical and HCl.

The second step involves the reaction of this methylene chloride got in the first step with chlorine molecule to form trichloride methane and a chlorine radical.

You would find in the attachment the 2 step mechanism.

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A sample of Ne gas has a pressure of 654 mmHg with an unknown volume. The gas has a pressure of 345 mmHg when the volume is 495m
Lemur [1.5K]

Answer:

The initial volume of Ne gas is 261mL

Explanation:

This question can be answered using Ideal Gas Equation;

However, the following are the given parameters

Initial Pressure = 654mmHg

Finial Pressure = 345mmHg

Final Volume = 495mL

Required

Initial Volume?

The question says that Temperature is constant;

This implies that, we'll make use of Boyle's law ideal gas equation which states;

P_1V_1 = P_2V_2

Where P_1 represent the initial pressure

P_2 represent the final pressure

T_1 represent the initial temperature

T_2 represent the final temperature

P_1 = 654mmHg\\P_2 = 345mmHg\\V_2 = 495mL

Substitute these values in the formula above;

654 * V_1 = 345 * 495

654V_1 = 170775

Divide both sides by 654

\frac{654V_1}{654} = \frac{170775}{654}

V_1 = \frac{170775}{654}

V_1 = 261.123853211

V_1 = 261mL (Approximated)

<em>The initial volume of Ne gas is 261mL</em>

7 0
3 years ago
The temperature at which there is no kinetic energy in an object . Is?? ASAP
Hatshy [7]
Zero hope this helps
7 0
4 years ago
Read 2 more answers
A student investigated the factors that affect math grades. Which statement from the lab report best represents a conclusion for
joja [24]

The correct answer choice from the statement above about investigated factors from lab results is :

Students who spend less time studying after school get lower math grade

Option D is the correct answer

<h3>What is mathlab?</h3>

This is an online platform where mathematics tutors help students to solve their difficulties in mathematics.

Mathematics is one of the most important aspect of knowledge in the education.

So therefore, The correct answer choice from the statement above about investigated factors from lab results is :

Students who spend less time studying after school get lower math grade

Learn more about MathLab:

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7 0
1 year ago
What is the volume of 70.0 g of ether if the density of ether is 0.70 g/mL?
frosja888 [35]
M=70.0 g
p=0.70 g/mL

v=m/p

v=70.0/0.70=100.00 mL
8 0
3 years ago
In a labratory activity the density of a sample of vanadium is determined to be 6.9g/cm^3 at room temperature. what is the perce
Snowcat [4.5K]

Answer:

c : 13%

Explanation:

Data Give:

Experimental density of vanadium = 6.9 g/cm³

percent error = ?

Solution:

Formula used to calculate % error

  % error = [experimental value -accepted value/accepted value] x 100

The reported accepted density value for vanadium = 6.11 g/cm³

Put value in the above equation

                  % error = [ 6.9 - 6.11 / 6.11 ] x 100

                  % error = [ 0.79 / 6.11 ] x 100

                  % error = [ 0.129] x 100

                  % error = 12.9

Round to the 2 significant figure

% error = 13 %

So, option c is correct            

7 0
3 years ago
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