Answer:
![\Delta U=-94.0J](https://tex.z-dn.net/?f=%5CDelta%20U%3D-94.0J)
Explanation:
Hello!
In this case, since the first law of thermodynamics allows us to understand how the energy behaves when heat and work are involved during a process, we can mathematically define it as:
![Q-W=\Delta U](https://tex.z-dn.net/?f=Q-W%3D%5CDelta%20U)
Whereas Q is the heat added to the system, W the work done by the system and ΔU the change in the internal energy, we can notice that since 97.0 J of work are done on the system it would be negative and the given off heat is also heat due to the used convention; therefore the change in its internal energy turns out:
![-191.0J-(-97.0J)=\Delta U\\\\\Delta U=-94.0J](https://tex.z-dn.net/?f=-191.0J-%28-97.0J%29%3D%5CDelta%20U%5C%5C%5C%5C%5CDelta%20U%3D-94.0J)
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Answer: the correct answer is a.
Explanation: a spreading of the sea floor is the correct answer.
Answer:
The molecules of oxygen should be placed as reactants in the equation.
Explanation:
1: N₂ + O₂ → 2NO
2: 2NO + O₂ → 2NO₂
complete reaction:
N₂ + 2O₂ → 2NO₂
- In both intermediate equations' oxygen is used as reactant because the end product is the product of the combination of nitrogen and oxygen. So in the complete or overall reaction, oxygen should also be placed as reactant.
We can not place oxygen at the side of products neither we can cancel it because, products can only be obtained at the end of the reaction but according to the equations' oxygen is not the end product of the reaction. But the addition into the reaction (Eq. 2) to make the new product.
Also, we can not cancel it because to cancel out molecules of oxygen should be present at the both sides with same amount in the stoichiometric equation.
Hence, in a balanced chemical equation, oxygen should be written as a reactant by using the correct number of moles.
Answer:
Wavelength of sound waves
millimetres
Explanation:
The speed of any wave is equal to the product of its wavelength and frequency.
This can be represented mathematically as
![V = f* \lambda](https://tex.z-dn.net/?f=V%20%20%3D%20f%2A%20%5Clambda)
Where
V is the speed of sound waves
f is the frequency of sound waves
and
is the wavelength of the sound waves.
Substituting the given values in above equation we get -
![340 = f * \lambda\\\lambda = \frac{340}{880} \\](https://tex.z-dn.net/?f=340%20%3D%20f%20%2A%20%5Clambda%5C%5C%5Clambda%20%3D%20%5Cfrac%7B340%7D%7B880%7D%20%5C%5C)
meters
millimetres