Jackie set her watch 19 seconds behind, and it falls behind another 1 second every day.
1 answer:
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Answer:
We can use the sample about 42 days.
Step-by-step explanation:
Decay Equation:
Integrating both sides
When t=0, N= = initial amount
.......(1)
.........(2)
Logarithm:
130 days is the half-life of the given radioactive element.
For half life,
,
days.
we plug all values in equation (1)
We need to find the time when the sample remains 80% of its original.
We can use the sample about 42 days.
To answer this question, we will use the sine law which is illustrated in the attached image.
We are given that:
The distance from school to library = a
∠A = 32
∠B = 110
b = 2.2
Substitute with the givens in the relation of the sine law to get a as follows:
(sin 32) / (a) = (sin 110) / (2.2)
a = (2.2 sin 32) / (sin 110)
distance from school to library = a = 1.2406 mi
Based on the above calculations, the best choice would be:
B. 1.2 mi
We are given that:
The distance from school to library = a
∠A = 32
∠B = 110
b = 2.2
Substitute with the givens in the relation of the sine law to get a as follows:
(sin 32) / (a) = (sin 110) / (2.2)
a = (2.2 sin 32) / (sin 110)
distance from school to library = a = 1.2406 mi
Based on the above calculations, the best choice would be:
B. 1.2 mi