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Katen [24]
2 years ago
11

If y = x3 + x, find the value of y when x=-2

Mathematics
2 answers:
zvonat [6]2 years ago
8 0

Answer:

y=-8

Step-by-step explanation:

if x=-2 -2*3= -6, -6+-2=-8

andrew-mc [135]2 years ago
5 0

Answer:

-8

Step-by-step explanation:

-2 times 3 is -6, and -6 plus -2 equals -8

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1/2 - [-1/4+2/3] how do you solve this value of the expression
Shkiper50 [21]

Answer:

1/12

Step-by-step explanation:

1/2-[-1/4+2/3]

1/2-[-3/12+8/12]

1/2-[5/12]

1/2-5/12

6/12-5/12

1/12

3 0
3 years ago
Hey can anyone help plz help me pls
fredd [130]

find the square root of 169

√169 is 13

= 13 feet

4 0
3 years ago
Read 2 more answers
All athletes at the Olympic Games (OG) are tested for performance-enhancing steroid drug use. The basic Anabolic Steroid Test (A
Semenov [28]

Answer:

a ) the probability of using steroids and having a negative test is 0.5%

b) The probability of testing positive is 6.4%

c) The probability of not using steroids, given that the test is negative is 99.47%

d) No, they are not statistically indepent.

e) The probability that the athlete will either use steroids or test positive is 6.9%

Step-by-step explanation:

Let A be the event that the test result is positive and B the event that the athlete uses Steroids. We are given the following

P(A|B) = 90%, P(A|B^c) = 2%, P(B) = 5%

From which we deduce that

P(A^c|B) = 10%, P(B^c) = 95%

a) We are asked for the probability P(A^c\cap B). REcall the conditional probability formula that, given two events C,D the conditional probability P(C|D) = \frac{P(C\cap D)}{P(D)}. Then we have that

P(A^c\cap B) = P(A^c|B)P(B) = 10\% \cdot 5\%=0.5\%.

b) We are asked for the probability P(A). We can use the fact that given two mutually exclusive events(that is, whose intersection is empty) A,B the probability P(C) of an event is given by P(C) = P(C|A)P(A)+P(C|B)P(B). Then

P(A) = P(A|B)P(B)+P(A|B^c)P(B^c) = 90\%\cdot5\% + 2\% \cdot 95% = 6.4\%

c) We are asked for the probability P(B^c|A^c). Recall that P(A|B) = \frac{P(B|A)P(A)}{P(B)}. Then

P(B^c|A^c) = \frac{P(A^c|B^c)P(B^c)}{P(A^c)}= \frac{P(A^c|B^c)P(B^c)}{1-P(A)}= \frac{(1-P(A|B^c))P(B^c)}{1-P(A)}=\frac{98\%\cdot 95\%}{1-6.4\%}= 99.47\%

d) We say that two events A,B are statistically indepent if P(A|B) = P(A). Note that from point B the probability of testing negative is 1- 6.4% = 93.6%. Since 93.6% is different from 99.47% this means that testing positive and using steroids are not statistically independent.

e) We are asked for the probability P(A\cup B). We use the following

P(A\cupB) = P(A)+P(B)-P(A\cap B) = P(A) +P(B)-P(A|B)P(B) = 6.4\%+5\%-90\%\cdot 5\%=6.9\%

4 0
4 years ago
What is the ratio or rate of 96 words typed in 3 min ; 160 words typed in 5 min
Vanyuwa [196]
32 because 96 divded by 3 equals 32 and 160 divided by 5 equals 32
4 0
4 years ago
Michael breeds chickens and ducks. Last month, he sold 505050 chickens and 303030 ducks for \$550$550dollar sign, 550. This mont
GenaCL600 [577]
Let the cost of a chicken be x and the cost of a duck, y, then

50x + 30y = 550 . . . (1)
44x + 36y = 532 . . . (2)

(1) x 6 ⇒ 300x + 180y = 3,300 . . . (3)
(2) x 5 ⇒ 220x + 180y = 2,660 . . . (4)

(3) - (4) ⇒ 80x = 640
⇒ x = 640 / 80 = 8

From (1): 50(8) + 30y = 550
⇒ 30y = 550 - 400 = 150
⇒ y = 150 / 30 = 5

Therefore, the price of a chicken is $8 and the price of a duck is $5.
4 0
4 years ago
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