<span><span>x3</span>+3<span>x2</span>−9x−27=<span>(x−3)</span><span>(x+3)</span><span>(x+3<span>)</span></span></span>
Answer:
31.04%
Step-by-step explanation:
So he increased 17%, then increased 12%.
When he increased by 17%, his height was 117%, relative to his former height. 12% of 117% is 14.04%
So he increase 17%, then increased 14.04% ( of his original height) so his total growth was 31.04%
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
Step-by-step explanation:
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