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Otrada [13]
3 years ago
5

Iron-59 is used in medicine to diagnose blood circulation disorders. The half life of iron-59 is 44.5 days. How much of a 2.000

mg sample will remain after 133.5 days? Show your work
Chemistry
1 answer:
kolezko [41]3 years ago
7 0

Answer:

0.258 mg of iron remains.

Explanation:

To solve this problem we can use the formula

M₂ = M₀ * 0.5^{\frac{t}{44.5} }

Where M₂ is the mass remaining, M₀ is the initial mass, and t is time in days.

Using the data given by the problem:

M₂ = 2.000 mg * 0.5^{\frac{133.5}{44.5} }

M₂ = 0.258 mg

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Chooses the name of the cellular process that match the organelle shown
otez555 [7]

Answer:

chloroplast photosynthesis

Explanation:

Photosynthesis is the process by which green plants create their own food by turning light energy into chemical energy. ... Cellular respiration, on the other hand, is the process by which living things convert oxygen and glucose to carbon dioxide and water, thereby yielding energy.

5 0
3 years ago
34.1 mg NaCl in 117.3 mL of solution
Solnce55 [7]

The molarity of the solution will be 4.97 M.

<h3>What is molarity?</h3>

It is the number of moles of solutes per 1 liter of solvent or solution.

Mole of 34.1 g NaCl = 34.1/58.44 = 0.5835 mol

117.3 mL = 117.3/1000 = 0.1173 L

Molarity of the solution = 0.5835/0.1173 = 4.97 M

More on molarity can be found here: brainly.com/question/2817451

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6 0
2 years ago
Butane C4H10 (g),(Hf = –125.7), combusts in the presence of oxygen to form CO2 (g) (Delta.Hf = –393.5 kJ/mol), and H2O(g) (Delta
shusha [124]

Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ

Explanation:

The balanced chemical reaction is,

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

The expression for enthalpy change is,

\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]

Putting the values we get :

\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]

\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]

\Delta H=-5314.8kJ

2 moles of butane releases heat = 5314.8 kJ

1 mole of butane release heat = \frac{5314.8}{2}\times 1=2657.4kJ

Thus enthalpy of combustion per mole of butane is -2657.4 kJ

3 0
3 years ago
A sample of a gas occupies 6.00 liters at a temperature of 200 K. If the pressure remains constant and the temperature is raised
egoroff_w [7]

Answer:

18

Explanation:

4 0
3 years ago
How long dows it take a moon to reacg a ful phase
FrozenT [24]

Answer:

about 29.5 days

Explanation:

it takes 27 days, 7 hours and 43 mins for our moon to complete a full orbit around the earth.

6 0
3 years ago
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