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kkurt [141]
3 years ago
5

How does ionization energy increase on the periodic table

Chemistry
2 answers:
Sladkaya [172]3 years ago
8 0

\huge \bf༆ Answer ༄

The trends showing increase in ionization energy on the periodic table ~

  • Ionization energy increases as we move from left to right in a period.

[ due to increase in effective nuclear charge ]

  • Ionization energy increases as we move from bottom to top in a group.

[ Due to decrease in number of shells ]

vodomira [7]3 years ago
5 0

Ionization energy increases across a period from left to right in the periodic  table.

<h2>Ionization energy</h2>

Ionization energy is the energy needed for the complete removal of valence electrons in its ground state from an isolated atom in its gaseous phase at a specified temperature to form an ion.

Ionization energy shows periodicity in that it shows a regular variation across a period and down a group in the periodic table.

Ionization energy increases across a period from left to right in the periodic  table.

Learn more about ionization energy at: brainly.com/question/1445179

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Because of movements at the Mid-Atlantic Ridge, the Atlantic Ocean widens by about 2.5 centimeters each year. Explain which type
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Answer:

A divergent plate boundary  

Explanation:

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6 0
4 years ago
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How many moles are there in 5.24 Liters of NH3 gas at STP?
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34.3

Explanation:

3 0
3 years ago
A gas has a volume of 1.75L at -23C and 150.0kPa. At what temperature would the gas occupy 1.30L at 210.0kPa?
Katen [24]

Answer:

T2 = 260 K  

Explanation:

<em>Given data:</em>

P1 = 150.0 k Pa

T1 = (-23+ 273.15) K = 250.15 K  

V1 = 1.75 L  

P2 = 210.0 kPa  

V2 = 1.30 L

<em>To find:</em>

T2 = ?

<em>Formula:</em>

\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}

T_2 = \frac{P_2 V_2 T_1}{P_1 V_1}

<em>Calculation:</em>

T2 = (210.0 kPa) x (1.30 L) x (250.15 K) / (150.0 kPa) x (1.75 L)

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8 0
4 years ago
Calculate the pka of hypochlorous acid. The ph of a 0.015 m solution of hypochlorous acid has a ph of 4.64.
o-na [289]

Answer:

  • pKa = 7.46

Explanation:

<u>1) Data:</u>

a) Hypochlorous acid = HClO

b) [HClO} = 0.015

c) pH = 4.64

d) pKa = ?

<u>2) Strategy:</u>

With the pH calculate [H₃O⁺], then use the equilibrium equation to calculate the equilibrium constant, Ka, and finally calculate pKa from the definition.

<u>3) Solution:</u>

a) pH

  • pH = - log [H₃O⁺]

  • 4.64 = - log [H₃O⁺]

  • [H_3O^+]= 10^{-4.64} = 2.29.10^{-5}

b) Equilibrium equation: HClO (aq) ⇄ ClO⁻ (aq) + H₃O⁺ (aq)

c) Equilibrium constant: Ka =  [ClO⁻] [H₃O⁺] / [HClO]

d) From the stoichiometry: [CLO⁻] = [H₃O⁺] = 2.29 × 10 ⁻⁵ M

e) By substitution: Ka = (2.29 × 10 ⁻⁵ M)² / 0.015M = 3.50 × 10⁻⁸ M

f) By definition: pKa = - log Ka = - log (3.50 × 10 ⁻⁸) = 7.46

5 0
4 years ago
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marshall27 [118]

Answer:

a) 3

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c) 1

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