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3 years ago

Calculate the molar mass of NH4NO3.

Chemistry

1 answer:

ozzi3 years ago

7 0

Answer:

80.043 g/mol

Explanation:

Ammonium nitrate is a chemical compound, the nitrate salt of the ammonium cation. It has the chemical formula NH ₄NO ₃, simplified to N₂H₄O₃. It is a white crystalline solid and is highly soluble in water. It is predominantly used in agriculture as a high-nitrogen fertilizer.

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Two airplanes are flying in the sky in such a way that the gravitational attractions between them decreases. The planes must be

masya89 [10]

A. away from each other

8 0

3 years ago

Calculate the amount of energy when water at 72 degrees c freezes completely at 0 degrees c

gtnhenbr [62]

Answer:

The amount of energy needed when water at 72 degrees c freezes completely at 0 degrees c is $6.37\times10^4$ Joules

Explanation:

$Q = m \times c \times \Delta T$

where

$\Delta T$ = Final T - Initial T

$Q_{1}=100 g \times 4.184 \frac{J}{g^{\circ} \mathrm{C}} \times\left(72^{\circ} \mathrm{C}-0^{\circ} \mathrm{C}\right)$

$Q_1$ =30125J

Q is the heat energy in Joules

c is the specific heat capacity (for water 1.0 cal/(g℃)) or 4.184 J/(g℃)

m is the mass of water

mass of water is assumed as 100 g (since not mentioned)

$Q_2$ is the heat energy required for the phase change

$Q_2$ =mass × heat of fusion

$\\$Q_{2}=100 g \times 336 \frac{J}{g}$\\\\$Q_{2}=33600 J$$

Total heat = $Q_1 + Q_2$

Total Heat = 30123J + 33600J

= 63725 J

= $6.37\times10^4$ Joules is the answer

3 0

3 years ago

Two perfumes are released at the same time. If one is standing 7.5 m from the point of release. Perfume A (molar mass 275 g/mol)

natta225 [31]

According to Graham's Law of Diffusion," Diffusion of Gas is inversely proportional to square root of its Molecular Mass or Density".

rᵇ/rᵃ =   $\sqrt{da/db}$
Or,
  rᵇ/rᵃ =   $\sqrt{Ma/Mb}$ ----- (1)
As,
Ma = 275 g/mol

Mb = 205 g/mol

Putting Values in eq.1,

rᵇ/rᵃ =   $\sqrt{275/205}$

rᵇ/rᵃ = 1.15

Result:
Perfume B will diffuse 1.15 times faster than Perfume A. Hence, Perfume B will be first smelled by the person.

6 0

3 years ago

A TLC plate showed 2 spots with Rf values of 0.25 and 0.26. The plate was removed from the developing chamber, the residual solv

Katena32 [7]

Answer:

See explanation

Explanation:

TLC is a chromatographic method in which the solute is spotted on a plate and the plate is placed in an air tight chamber containing a solvent. The solvent is maintained below the level of the spot. The capillary movement of the solvent through the plate achieves the required separation.

If two spots have Rf values of 0.25 and 0.26 respectively and then the plate was removed from the developing chamber, subsequently, the residual solvent was allowed to evaporate from the plate, and then the plate was returned to the developing chamber.

It will be observed after the second development is complete that the new Rf values will be 0.50 and 0.52 respectively. It will just be as though the second chromatogram picked up from where the first chromatogram stopped.

4 0

3 years ago

Find the volume of a gas at STP, if its volume is 80.0 mL at 109 kPa and -12.5°C.

exis [7]

Answer:

= 913.84 mL

Explanation:

Using the combined gas laws

P1V1/T1 = P2V2/T2

At standard temperature and pressure. the pressure is 10 kPa, while the temperature is 273 K.

V1 = 80.0 mL

P1 = 109 kPa

T1 = -12.5 + 273 = 260.5 K

P2 = 10 kPa

V2 = ?

T2 = 273 K

Therefore;

V2 = P1V1T2/P2T1

= (109 kPa × 80 mL × 273 K)/(10 kPa× 260.5 K)

= 913.84 mL

5 0

3 years ago

Read 2 more answers