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3 years ago

What is the common denominator for 3/5+3/4

Mathematics

2 answers:

tino4ka555 [31]3 years ago

7 0

Answer:

LCD (3 /5 , 3/ 4 ) = LCM(5, 4) = 2²×5 = 20

Step-by-step explanation:

The lowest common denominator or least common denominator (abbreviated LCD) is the least common multiple of the denominators of a set of fractions. It is the smallest positive integer that is a multiple of each denominator in the set.

nadezda [96]3 years ago

3 0

The common denominator is 20

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Please help <br> multiple choice<br> picture included <br> will appreciate it if you help!

Bond [772]

Answer:

Step-by-step explanation:

The quotient of 2 and n is 2/n, not n/2, and if it's at most 6 that means it can equal 6 but can't go above it, so it's less than or equal to six. Hope this helped!

8 0

3 years ago

Gas is being pumped into a tank the total amount of gas G after amount of time T is given by the equation G= 50+20t if the total

luda_lava [24]

Answer:

T = 40 (minutes?)

Step-by-step explanation:

Given the equation G = 50 + 20T, where G = the total amount of gas and T = the amount of Time, we know that there is already 50 gallons of gas in the tank and that the rate at which it is pumped is 20 gallons per minute (I am assuming, though it is not stated in the problem). Given that the tank holds 850 gallons, we can plug in the values into the equation and solve for the missing variable, T:

850 = 50 + 2T

Subtract 50 from both sides: 850 - 50 = 50 + 2T - 50 or 800 = 2T

Divide 2 from both sides: 800/2 = 2T/2

Solve for T: 40 = T

3 0

3 years ago

A 200-gal tank contains 100 gal of pure water. At time t = 0, a salt-water solution containing 0.5 lb/gal of salt enters the tan

Artyom0805 [142]

Answer:

1) $\frac{dy}{dt}=2.5-\frac{3y}{2t+100}$

2) $y(t)=(50+t)- \frac{12500\sqrt{2} }{(50+t)^{\frac{3}{2} }}$

3) 98.23lbs

4) The salt concentration will increase without bound.

Step-by-step explanation:

1) Let $y$ represent the amount of salt in the tank at time t, where t is given in minutes.

Recall that: $\frac{dy}{dt}=rate\:in-rate\:out$

The amount coming in is $0.5\frac{lb}{gal}\times 5\frac{gal}{min}=2.5\frac{lb}{min}$

The rate going out depends on the concentration of salt in the tank at time t.

If there is $y(t)$ pounds of salt and there are $100+2t$ gallons at time t, then the concentration is: $\frac{y(t)}{2t+100}$

The rate of liquid leaving is is 3gal\min, so rate out is $=\frac{3y(t)}{2t+100}$

The required differential equation becomes:

$\frac{dy}{dt}=2.5-\frac{3y}{2t+100}$

2) We rewrite to obtain:

$\frac{dy}{dt}+\frac{3}{2t+100}y=2.5$

We multiply through by the integrating factor: $e^{\int \frac{3}{2t+100}dt }=e^{\frac{3}{2} \int \frac{1}{t+50}dt }=(50+t)^{\frac{3}{2} }$

to get:

$(50+t)^{\frac{3}{2} }\frac{dy}{dt}+(50+t)^{\frac{3}{2} }\cdot \frac{3}{2t+100}y=2.5(50+t)^{\frac{3}{2} }$

This gives us:

$((50+t)^{\frac{3}{2} }y)'=2.5(50+t)^{\frac{3}{2} }$

We integrate both sides with respect to t to get:

$(50+t)^{\frac{3}{2} }y=(50+t)^{\frac{5}{2} }+ C$

Multiply through by: $(50+t)^{-\frac{3}{2}}$ to get:

$y=(50+t)^{\frac{5}{2} }(50+t)^{-\frac{3}{2} }+ C(50+t)^{-\frac{3}{2} }$

$y(t)=(50+t)+ \frac{C}{(50+t)^{\frac{3}{2} }}$

We apply the initial condition: $y(0)=0$

$0=(50+0)+ \frac{C}{(50+0)^{\frac{3}{2} }}$

$C=-12500\sqrt{2}$

The amount of salt in the tank at time t is:

$y(t)=(50+t)- \frac{12500\sqrt{2} }{(50+t)^{\frac{3}{2} }}$

3) The tank will be full after 50 mins.

We put t=50 to find how pounds of salt it will contain:

$y(50)=(50+50)- \frac{12500\sqrt{2} }{(50+50)^{\frac{3}{2} }}$

$y(50)=98.23$

There will be 98.23 pounds of salt.

4) The limiting concentration of salt is given by:

$\lim_{t \to \infty}y(t)={ \lim_{t \to \infty} ( (50+t)- \frac{12500\sqrt{2} }{(50+t)^{\frac{3}{2} }})$

As $t\to \infty$ , $50+t\to \infty$ and $\frac{12500\sqrt{2} }{(50+t)^{\frac{3}{2} }}\to 0$

This implies that:

$\lim_{t \to \infty}y(t)=\infty- 0=\infty$

If the tank had infinity capacity, there will be absolutely high(infinite) concentration of salt.

The salt concentration will increase without bound.

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3 years ago

Finish the following table for the given function with x as thr independent variable.

konstantin123 [22]

The answer is c.0.1,0.05.0.025.
We can find these by substituting the x values on the table given into the equation; h(x)=1/x.

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3 years ago

Read 2 more answers

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Jlenok [28]

Answer:

The correct definition of statistics is

B. Statistics is the science of collecting, organizing, summarizing, and analyzing information to draw a conclusion and answer questions. In addition, statistics is about providing a measure of confidence in any conclusions.

Explanation:

Statistics is the science of collecting, organizing, summarizing, and analyzing the information and based on this information a conclusion is drawn about the collected information. There are two main divisions of statistics:

1. Descriptive statistics: It deals with providing the summary about the information collected.

2. Inferential statistics: This division deals with using a sample from the population and drawing the conclusion about the population using the sample. It also includes providing a measure of confidence in any conclusions.

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4 years ago