3 years ago

Suppose a bag contains 7 blue chips ad 3 gold chips.What is the probability of randomly choosing a gold chip,not replacing it,an

d then randomly choosing another gold chip

1 answer:

6 0

$|\Omega|=10\cdot9=90\\ |A|=3\cdot2=6\\\\ P(A)=\dfrac{6}{90}=\dfrac{1}{15}\approx7\%$

You might be interested in

mars1129 [50]

Add like terms and put x in the middle.
-3 < -2x + x - 3x ≤ 5 - 2
-3 < - 4x ≤ 3
Sign changed when divide by negative numbers
(3/4) > x ≥ (-3/4)

4 0

3 years ago

IgorLugansk [536]

Answer:

=18

Step-by-step explanation:

3 0

3 years ago

Dima020 [189]

3.65x19.8=$72.07 hit that thanks button and 5 star rating plz thankyou!!!!

7 0

3 years ago

Stells [14]

Answer:

The answer to that question is c. y = x

8 0

3 years ago

Aliun [14]

The answer to you question I think is 7

8 0

3 years ago