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3 years ago

Find the zeros of the function F(x)=x^2-9x-9

Mathematics

1 answer:

Marta_Voda [28]3 years ago

8 0

F(x)=x^3+x^2-9x-9
x^2(x+1)-9(x+1)
=(x+1)(x^2-9)

=(x+1)(x+3)(x-3)
Hope that this helps

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3 years ago

Forty percent of households say they would feel secure if they had $50,000 in savings. you randomly select 8 households and ask

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$P(x=r)=^nC_r p^r q^{n-r}$

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(b) the probability of the number that say they would feel secure is more than five

$P(X>5) = P(X=6)+ P(X=7) + P(X=8)$

$=^8C_6 (0.4)^6 (0.6)^{8-6}+^8C_7 (0.4)^7 (0.6)^{8-7}+^8C_8 (0.4)^8 (0.6)^{8-8}$

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(c) the probability of the number that say they would feel secure is at most five

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$=^8C_0 (0.4)^0(0.6)^{8-0}+^8C_1(0.4)^1(0.6)^{8-1}+^8C_2 (0.4)^2 (0.6)^{8-2}+8C_3 (0.4)^3 (0.6)^{8-3}+8C_4 (0.4)^4 (0.6)^{8-4}+8C_5(0.4)^5 (0.6)^{8-5}$