3 years ago

Find the zeros of the function F(x)=x^2-9x-9

1 answer:

8 0

F(x)=x^3+x^2-9x-9
x^2(x+1)-9(x+1)
=(x+1)(x^2-9)

=(x+1)(x+3)(x-3)
Hope that this helps

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e-lub [12.9K]

4(4x)+(x)

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Combine like terms

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I hope that's help ! Good night .

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3 years ago

Aleks04 [339]

I will take110+110 which will give me220

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3 years ago

pogonyaev

I assume you're looking for the number:
0.5n + 9 = 21
- 9
0.5n = 12
÷ 0.5
n = 24
So the beginning number is 24, hope this helps!

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dusya [7]

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Reil [10]

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3/2

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3 years ago