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3 years ago

Find the zeros of the function F(x)=x^2-9x-9

Mathematics

1 answer:

Marta_Voda [28]3 years ago

8 0

F(x)=x^3+x^2-9x-9
x^2(x+1)-9(x+1)
=(x+1)(x^2-9)

=(x+1)(x+3)(x-3)
Hope that this helps

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(x+3)(3x² - 5x - 10) multiply polynomial

brilliants [131]

Answer:

$\boxed{\sf{3x^3+4x^2-25x-30}}$

Step-by-step explanation:

$\underline{\text{SOLUTION:}}$

To isolate the term of x from one side of the equation, you must multiply by a polynomial.

$\underline{\text{GIVEN:}}$

$:\Longrightarrow: \sf{(x+3)(3x^2 - 5x - 10)}$

You have to solve with parentheses first.

$:\Longrightarrow \sf{x\cdot \:3x^2+x\left(-5x\right)+x\left(-10\right)+3\cdot \:3x^2+3\left(-5x\right)+3\left(-10\right)}$

Solve.

$\sf{x*3x=3x^3}$

x(-5x)=-5x²

$\sf{x(-10)=-10x}$

3*3x²=9x²

3(-5x)=-15x

3(-10)=-30

Then, rewrite the problem down.

$\sf{3x^3-5x^2-10x+9x^2-15x-30}$

Combine like terms.

$\Longrightarrow: \sf{3x^3-5x^2+9x^2-10x-15x-30}$

Add/subtract the numbers from left to right.

-5x²+9x²=4x²

$\Longrightarrow: \sf{3x^3+4x^2-10x-15x-30}$

Solve.

$\sf{-10x-15x=-25x}$

Then rewrite the problem.

$\Longrightarrow: \boxed{\sf{3x^3+4x^2-25x-30}}$

Therefore, the correct answer is 3x³+4x²-25x-30.

I hope this helps! Let me know if you have any questions.

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