Answer:
C. -2 and -1
Step-by-step explanation:
-1.5 is bigger than -2 but smaller than -1.
Thus, it is between these two number
Answer/Step-by-step explanation:
(a) The likelihood function to estimate this probability can be written as:
mat[1000, 9800]p9580(1 - p)420
(b) The value of the maximum likelihood estimate of the probability 0.958(By taking log of expression in (a) above)
(c) when the true probability is 98%, then it implies that 9800 of 10,000 bulbs did last over 6500hours.
Therefore, the likelihood is p(9800) = mat[10000, 9800]p9800(1 - p)200
(d) Method of moments estimate is the estimation of all the parameters of the population sample.
(e) The statement is FALSE because estimates by the method of moments are not necessarily sufficient statistics, because sometimes fail to take into account all relevant information in the sample. As in the above question
Domain: (infinity, 4]
range: [-6, infinity)
Answer:
a. 25.98i - 15j mi/h
b. 1.71i + 4.7j mi/h
c. 27.69i -10.3j mi/h
Step-by-step explanation:
a. Identify the ship's vector
Since the ship moves through water at 30 miles per hour at an angle of 30° south of east, which is in the fourth quadrant. So, the x-component of the ship's velocity is v₁ = 30cos30° = 25.98 mi/h and the y-component of the ship's velocity is v₂ = -30sin30° = -15 mi/h
Thus the ship's velocity vector as ship moves through the water v = v₁i + v₂j = 25.98i + (-15)j = 25.98i - 15j mi/h
b. Identify the water current's vector
Also, since the water is moving at 5 miles per hour at an angle of 20° south of east, this implies that it is moving at an angle 90° - 20° = 70° east of north, which is in the first quadrant. So, the x-component of the water's velocity is v₃ = 5cos70° = 1.71 mi/h and the y-component of the water's velocity is v₄ = 5sin70° = 4.7 mi/h
Thus the ship's velocity vector v' = v₃i + v₄j = 1.71i + 4.7j mi/h
c. Identify the vector representing the ship's actual motion.
The velocity vector representing the ship's actual motion is V = velocity vector of ship as ship moves through water + velocity vector of water current.
V = v + v'
= 25.98i - 15j mi/h + 1.71i + 4.7j mi/h
= (25.98i + 1.71i + 4.7j - 15j )mi/h
= 27.68i -10.3j mi/h
