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DaniilM [7]
3 years ago
5

If the vapor pressure of an aqueous solution containing 6.00 moles of a nonvolatile solute has a vapor pressure of 19.8 torr, an

d given that the vapor pressure of water at room temperature is 23.7 torr, how many total moles are present in solution?
Chemistry
1 answer:
lisov135 [29]3 years ago
6 0

Answer:

36.4 moles

Explanation:

This is a problem where a solute is added to water and this then decreases the vapor pressure of the water from what it was when it was pure.  The amount it will decrease the vapor pressure is directly related to the mole fraction of the solute (or put another way, the mole fraction of the water).

mole fraction of water x vapor pressure of water = vapor pressure of solution.  In equation form it is ...

Psolution = Xsolvent x P0solvent

We can solve for Xsolvent which is the mole fraction of the water.

Xsolvent = Psolution/Posolvent

Xsolvent = 19.8 torr/23.7 torr = 0.835

Since there are 6.00 moles of solute, we can find total moles present in solution.

x moles water/6.00 moles solute + x moles water = 0.835

x = 30.4 moles of water

Total moles present in solution = 6.00 moles + 30.4 moles = 36.4 moles

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b) 5.87 E23 molecules

Explanation:

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A blood specimen is collected in a heparin-containing tube for calcium and magnesium determination. Upon centrifugation, the pla
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False hypermagnesaemia

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Define the term valence electron and explain how to find the number of valence electrons in family one and family 2.
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8 0
4 years ago
A 216-L cylinder holds propane gas at 184.8 kPa of pressure and 127°C. How many moles of propane are in the cylinder?
lbvjy [14]

Answer:

12 moles of propane.

Explanation:

From the question given above, the following data were obtained:

Volume (V) = 216 L

Pressure (P) = 184.8 KPa

Temperature (T) = 127 °C

Number of mole (n) =?

Next, we shall convert 127 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 127 °C

T(K) = 127 + 273

T(K) = 400 K

Finally, we shall determine the number of mole of propane gas in the container. This can be obtained as follow:

Volume (V) = 216 L

Pressure (P) = 184.8 KPa

Temperature (T) = 400 K

Gas constant (R) = 8.314 L.KPa/Kmol

Number of mole (n) =?

PV = nRT

184.8 × 216 = n × 8.314 × 400

39916.8 = n × 3325.6

Divide both side by 3325.6

n = 39916.8 / 3325.6

n = 12 moles

Thus, 12 moles of propane is present in the cylinder

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The answer to this question is A.) Salad
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