Answer:
hope this helps
Explanation:
glycosidic bond
A covalent bond formed between a carbohydrate molecule and another molecule (in this case, between two monosaccharides) is known as a glycosidic bond (Figure 4). Glycosidic bonds (also called glycosidic linkages) can be of the alpha or the beta type.
Answer:
The pH of the solution is 12.31 .
Explanation:
Initial molarity of barium hydroxide =
Initial volume of barium hydroxide =
Final molarity of barium hydroxide =
Final volume of barium hydroxide =
1 mol of barium gives 2 mol of hydroxide ions.
Then 0.0104 M of barium hydroxide will give:
of hydroxide ions
![[OH^-]=0.0208 M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D0.0208%20M)
![pH=14-pOH=14-(-\log[OH^-])](https://tex.z-dn.net/?f=pH%3D14-pOH%3D14-%28-%5Clog%5BOH%5E-%5D%29)
![pH=14-(-\log[0.0208 M])=12.31](https://tex.z-dn.net/?f=pH%3D14-%28-%5Clog%5B0.0208%20M%5D%29%3D12.31)
The pH of the solution is 12.31 .
Answer:
600 black men
Explanation:
309 with syphilis and 201 did not have the disease
Answer:
It is an saturated compound since there are no c-c double or tripple bonds.
Explanation:
If we had such double or tripple bonds the remaining o &H atoms cannot be accommodated to the carbon chain.
the carbon skeleton has (26×2)+6=58 valence electrons
O occupies 2 for each
18×2= 36
,58-36=22
only 22H can be directly bonded to the carbon skeleton.
remaining H= 14
therefore 7carbonyl carbon atoms will have to turn into carbinol carbon atoms .
so no space for c-c double bonds
Answer:
% yield = 62.21 %
Explanation:
- C2H4(g) + H2O(l) → C2H6O(l)
∴ mass C2H4(g) = 4.6 g
∴ mass C2H6O(l) = 4.7 g
- % yield = ((real yield)/(theoretical yield))×100
theretical yield:
∴ molar mass C2H4(g) = 28.05 g/mol
⇒ mol C2H4(g) = (4.6 g)*(mol/28.05 g) = 0.164 mol
⇒ mol C2H6O(l) = (0.164 mol C2H4)*(mol C2H6O(l)/molC2H4(g))
⇒ mol C2H6O(l) = 0.164 mol
∴ molar mass C2H6O(l) = 46.07 g/mol
⇒ mass C2H6O(l) = (0.164 mol)*(46.07 g/mol) = 7.55 g
⇒ theoretical yield = 7.55 g
⇒ % yield = (4.7 g)/(7.55 g))*100
⇒ % yield = 62.21 %
