Answer:
The molarity is 0.203 M
Explanation:
Using the formula C(oxi) x V(oxi) / [C(red) x V(red)] = N(oxi) / N(red)
Where oxi and red means reducing agent and oxidising agent respectively.
C = Concentration, V = Volume and N = number of moles.
C(oxi) = 0.5 M
V(oxi) = mL
C(red) = ?
V(red) = 30mL
Equation of reaction = 2K2S2O3 + KI3 = K2S4O6 + 3KI
so N(red) = 1 , N(oxi) = 2
from the equation above,
C(red) = 0.5 x 25 x 1 / (2 x 30)
= 0.203 M.
The appropriate response is Aluminum. It has higher in the movement arrangement than a nickel. Aluminum metal is so artificially responsive that local examples are uncommon and constrained to outrageous decreasing conditions. Rather, it is discovered joined in more than 270 unique minerals.
1. Decreases by 4. (B)
2. The atomic number changes. (B)
3. 56/26 Fe. (C)
4. Potassium-40;t1/2=25 days. (B)
5. Takes place in the upper atmosphere. (A)
Answer:
8.66 g of Al₂O₃ will be produced
Explanation:
4Al (s) + 3O₂ (g) → 2Al₂O₃ (s)
This is the reaction.
Problem statement says, that the O₂ is in excess, so the limiting reactant is the Al. Let's determine the moles we used.
4.6 g / 26.98 g/mol = 0.170 moles
Ratio is 4:2.
4 moles of aluminum can produce 2 moles of Al₂O₃
0.170 moles of Al, may produce (0.170 .2)/ 4 = 0.085 moles
Let's convert the moles of Al₂O₃ to mass.
0.085 mol . 101.96 g/mol = 8.66 g
Answer:
A. 0.295 mole
B. 0.055 mole
C.0.144 mole
D. 0.03 mole
Explanation:
To find the amount in moles, we simply use a mathematical relation that connects mass, atomic mass and number of moles.
Number of moles = mass/atomic mass
A. Atomic mass of Argon is 40
n = 11.8/40 = 0.295 mole
B. Atomic mass of zinc is 65
n = 3.55/65 = 0.055 mole
C. Atomic mass of Tantalum is 181
n = 26.1/181 = 0.144 mole
D. Atomic mass of lithium is 7
n = 0.211/7 = 0.03 mole
