Answer:
Mass of water = 6251. 706g or 6.25Kg
Explanation:
Relative humidity = (actual vapor pressure/saturation vapor pressure) * 100%
Actual vapor pressure, Pw = relative humidity * saturation vapor pressure
Pw = 60% * (35.6 *0.001)atm = 0.0216atm
Note: 1mbar = 0.001atm
Using the ideal gas equation: PV=nRT; where P = Pw= 0.02136atm, V= (400
* 1000)dm^3, R= 0.082 atmdm^3/kmol, T= (27+273)K, n = number of moles
Note: 1m^3 = 1000dm^3,R is the molar gas constant.
Making n subject of the formula, n = PV/RT
n= (0.02136 * 400000)/(0.082 * 300) = 347.317 moles
Mass (g) = number of moles (n) * molar mass
molar mass of water=18g
Mass of water = 347.317 * 18 = 6251. 706g or 6.25Kg
