
from the graph we can see that the vertex is at h = -2 and k = - 4, we also know that the parabola runs through the point (-1 , 0)
![\stackrel{vertex}{(\stackrel{h}{-2}~~,~~\stackrel{k}{-4})}\qquad y=a[x-(-2)]^2-4\implies \underline{y=a(x+2)^2-4} \\\\\\ \begin{cases} x=-1\\ y=0 \end{cases}\qquad \implies 0=a(-1+2)^2-4\implies 0=a-4\implies 4=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \underline{y=4(x+2)^2-4}~\hfill](https://tex.z-dn.net/?f=%5Cstackrel%7Bvertex%7D%7B%28%5Cstackrel%7Bh%7D%7B-2%7D~~%2C~~%5Cstackrel%7Bk%7D%7B-4%7D%29%7D%5Cqquad%20y%3Da%5Bx-%28-2%29%5D%5E2-4%5Cimplies%20%5Cunderline%7By%3Da%28x%2B2%29%5E2-4%7D%20%5C%5C%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20x%3D-1%5C%5C%20y%3D0%20%5Cend%7Bcases%7D%5Cqquad%20%5Cimplies%200%3Da%28-1%2B2%29%5E2-4%5Cimplies%200%3Da-4%5Cimplies%204%3Da%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20%5Cunderline%7By%3D4%28x%2B2%29%5E2-4%7D~%5Chfill)
Answer c, you have to put the equation in slope intercept form which is y=Mx+b so you would subtract the 3x and move it to the other side of the equal sign before the -2 so it would be 2y=-3x-2 then you would divide the 2 on both sides to separate the 2 from the y. -3x/2 is -3/2x 2/-2 is -1 so you answer would be C y= -3/2x - 1 Hope this makes since! Good luck!
Answer:
Options A, C and F are the correct options.
Step-by-step explanation:
Given inequality is,
x - 2.6 ≥ 9.4
x - 2.6 + 2.6 ≥ 9.4 + 2.6
x ≥ 12
Option A.
x ≥ 12 [Correct]
Option B.
x ≥ 6.8 [Incorrect]
Option C.
Since in this inequality there is a sign of equal to (=)
Therefore, A closed circle will be used.
This option is also correct.
Option D.
An open circle is used on the graph.
Incorrect.
Option E.
The arrow on the graph points left.
Incorrect.
Option F.
The arrow on the graph points right.
Correct.
0.9 x (12-2) + 0.6
0.9 x (14) + 0.6
12.6 + 0.6
13.2
I hope I helped
Please make me brainliest
It should be the red parachute that falls 10 feet in 4 seconds because it's falling at a rate of 0.5 ft/sec slower than the blue.