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antiseptic1488 [7]
3 years ago
15

What is the value of X I. The rhombus below? A. 25 B. 43 C. 47 D. 21

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
7 0

Answer:

Correct answer is 21. I believe someone said it was 25 earlier, they are wrong. 21 is correct. (D)

Step-by-step explanation:

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10.
Kay [80]

Answer:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.535 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.2 \leq \sigma \leq 2.8

And the best option would be:

A.  2.2 < σ < 2.8

Step-by-step explanation:

Information provided

\bar X=32.1 represent the sample mean

\mu population mean  

s=2.4 represent the sample standard deviation

n=83 represent the sample size  

Confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=83-1=82

The Confidence is given by 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=62.132

\chi^2_{1- \alpha/2}=104.139

And replacing into the formula for the interval we got:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.535 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.2 \leq \sigma \leq 2.8

And the best option would be:

A.  2.2 < σ < 2.8

3 0
3 years ago
Help meee please thank you will mark brainlist….
erik [133]

Answer:

It's 47 because it's an isosceles triangle.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Simplify y2+4y–16y+3y2.
nadya68 [22]

Answer:

4y^2-12y

Step-by-step explanation:

y^2+4y-16y+3y^2

=y^2+3y^2+4y-16y

=4y^2+4y-16y

=4y^2-12y

6 0
3 years ago
Find the solution of this system of equations.
german
16+ 44 so I =60 hdndmoaoaoajebdbvdjjssksk
8 0
3 years ago
Cheryl is now x years old. Her cousin is ⅓ Cheryl’s age. Find her cousin’s age in terms of x.
nikklg [1K]

x/3= her cousins age

4 0
3 years ago
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