Answer:
40.0⁰
Explanation:
The formula for calculating the magnetic flux is expressed as:
where:
is the magnetic flux
B is the magnetic field
A is the cross sectional area
is the angle that the normal to the plane of the loop make with the direction of the magnetic field.
Given
A = 0.250m²
B = 0.020T
= 3.83 × 10⁻³T· m²
3.83 × 10⁻³ = 0.020*0.250cosθ
3.83 × 10⁻³ = 0.005cosθ
cosθ = 0.00383/0.005
cosθ = 0.766
θ = cos⁻¹0.766
θ = 40.0⁰
<em>Hence the angle normal to the plane of the loop make with the direction of the magnetic field is 40.0⁰</em>
Answer:
1. The car which is twice as massive as the other will have twice potential energy.
Explanation:
The potential energy of an object is given by:
where
m is the mass of the object
g is the gravitational acceleration
h is the height of the object measured to some reference level
In this problem, we have two cars at same elevation (= same h in the formula) but one car has twice the mass of the second car. Calling m the mass of one car and 2m the mass of the second car, we have:
- Potential energy of the first car:
- potential energy of the second car:
So, the car which is twice as massive as the other will have twice potential energy.
Angular speed :
ω = D/t
D - rotational distance traveled, D = 2 π · 5.5 = 11 π
ω = 11π/3 rad / s ≈ 11.513 rad/s
Answer:
309 m
Explanation:
time apart = 0.8 s
speed of sound in air = 343 m/s
speed of sound in concrete = 3000 m/s
lets assume it time it takes to travel trough concrete = T
the time it takes to travel through air = T + 0.8 since they are 0.8 s apart
the distance traveled by both waves is the same, so we can equate the distance for both waves
distance = speed x time
- for concrete, distance = 3000 x T
- for air, distance = 343 x (T + 0.8)
now equating the two distance together we have
3000 x T = 343 x (T + 0.8)
3000T = 343T + 274.4
3000T - 343T = 274.4
T = 0.103 s
recall that distance = 3000 x T = 3000 x 0.103 = 309 m
Answer:
4.275v
<u><em>Thank you </em></u>
