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Answer:
m = 0.59 kg.
Explanation:
First, we need to find the relation between the frequency and mass on a spring.
The Hooke's law states that
And Newton's Second Law also states that
Combining two equations yields
The term that determines the proportionality between acceleration and position is defined as angular frequency, ω.
And given that ω = 2πf
the relation between frequency and mass becomes
.
Let's apply this to the variables in the question.
To solve this problem, we use the equation:
<span>d = (v^2 - v0^2) /
2a</span>
where,
d = distance of collapse
v0 = initial velocity = 101 km / h = 28.06 m / s
v = final velocity = 0
a = acceleration = - 300 m / s^2
d = (-28.06 m / s)^2 / (2 * - 300 m / s^2)
<span>d = 1.31 m</span>
Speed of any freely falling object is always same. Provided, both are left to fall from the same height. If you perform this experiment in a perfect vacuum or near vacuum laboratory, both of them will reach ground with same velocity this is because there is no resistance to their motion. This is always true no matter where you go and perform this experiment.
It can be easily proved from conservation of mechanical energy. Why conserving energy? because there are no forces acting on the freely falling objects other than conservative force(mg).