There u go tried my best to work it out!! :))
To fine the mean for a first add up all the players heights then divide by the number of players.
Mean=(198+199+200+201+202)÷5
=1000÷5
=200
The answer to a is 200
For question be were gonna say for now that the height of our new player is represented by x. So we know that together there is 6 players and we know our answer so it should look something like this
201= (199+198+199+200+201+202+x) ÷ 6
201=1000+x ÷ 6
Then Im going to multiply 201 by 6 to get rid of the 6 on the other side.
1206=1000+x
Then I’m going to subtract 1000 from both sides to get x by itself
206=x
So the new players height is 206 .
Answer:
i think the second question (the choose the Function) means choose the function that has changed the most.
the first choose function one, i dont know but... according to wikipedia, "an initial value problem is an ordinary differential equation together with an initial condition which specifies the value of the unknown function at a given point in the domain. Modeling a system in physics or other sciences frequently amounts to solving an initial value problem." hope this helps
Step-by-step explanation:
Click on the picture! This is the explanation in accident I deleted it hope it helps!
Consecutive integers are 1 apart
x,x+1,x+2
(x)(x+1)(x+2)=-120
x^3+3x^2+3x=-120
add 120 to both sides
x^3+3x^2+3x+120=0
factor
(x+6)(x^2-3x+20)=0
set each to zero
x+6=0
x=-6
x^2-3x+20=0
will yeild non-real result, discard
x=-6
x+1=-5
x+2=-4
the numbers are -4,-5,-6
use trial and error and logic
factor 120
120=2*2*2*3*5
how can we rearange these numbers in (x)(y)(z) format such that they multiply to 120?
obviously, the 5 has to stay since 2*5=10 which is out of range
so 2*2*2*3 has to arrange to get 3,4 or 4, 6 or 6,7
obviously, 7 cannot happen since it is prime
3 and 4 results in in 12, but 2*2*2*3=24
therfor answer is 4 and 6
they are all negative since negaive cancel except 1
the numbers are -4,-5,-6
