So let's break this question down.
You need a bit of both, right? Well we need to calculate how many multiple choices we can do whilst having true/false questions, and not going over or under on points.
So, let's pick a random number, 5. So let's do 8x5, that equals 40.
ohmygoditsrightiwasseriouslyjustguessing
Ok so now we have our number, 5 multiple choice questions.
The true/false questions should be easy, just do 3x20 and you get 60.
ANSWER: 5
Based on this question, one thing that we would seriously consider would be the fact of first, doing
first. By doing this, it would then give us our answer as 16. By us understanding this point of view, we would then consider that this would then be your answer. That would then include that there would then be 16 pairs of the "enantiomeric pairs", and that would then be the possible estimate.
<span>a.2
b.4
c.8
d.16</span>
(n*3)+6-(n*2)=n+3
3n+6-2n=n+3
3n-2n-n=3-6 every n on the left and free numbers on the right
0=-3
contradiction, there are no solution
I’m 99% sure it’s D because you would add both those numbers to equal his debt that day
Step-by-step explanation:
3x + 5y = 21 * (-4) •••••• -12x -20y = -84 (a)
4x - 2y = -24 * (3) •••••• 12x -6y = -72 (b)
(a) + (b)
-26y = -156
y = 6
3x + 5 * 6 = 21
3x = 21 - 30
3x = -9
x = -3
