3 years ago

I NEED HELP ASAP PLEASE HELP ME FILL THIS DOCUMENTATION OUT PLEASE .ILL GIVE U 50 POINTS

Mathematics

1 answer:

vesna_86 [32]3 years ago

3 0

Answer:

in the pictureeeeeeeeeeeeee

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Use this diagram and information given to find m

zaharov [31]

The drawing seems to suggest that angles BFA, AFE and EFD span a straight angle, just like angles BFC and CFD

This means that you have

$BFA+AFE+EFD=180$

But we know that both BFA and EFD measure 70 degrees, so the equation becomes

$[tex]70+AFE+70=180 \iff AFE + 140 = 180$

So, if you subtract 140 from both sides, you have

$AFE = 180-140 = 40$

5 0

3 years ago

Complete the point slope equation of the line through (-8,-8) &' (-7,9) y-9=

hram777 [196]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ -8 &,& -8~) 
% (c,d)
&&(~ -7 &,& 9~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{9-(-8)}{-7-(-8)}\implies \cfrac{9+8}{-7+8}
\\\\\\
\cfrac{17}{1}\implies 17
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_2= m(x- x_2)}\implies y-9=17[x-(-7)]
\\\\\\
y-9=17(x+7)$