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Kobotan [32]
3 years ago
7

I NEED HELP ASAP PLEASE HELP ME FILL THIS DOCUMENTATION OUT PLEASE .ILL GIVE U 50 POINTS

Mathematics
1 answer:
vesna_86 [32]3 years ago
3 0

Answer:

in the pictureeeeeeeeeeeeee

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Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the given sample data. An experiment was conducted to determin
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The mean phenotype code is 2.72

The median phenotype code is 2.52

The mode phenotype code is 2.

The midrange of the phenotype codes is 2.52

B Only the mode makes sense since the data is nominal.

Step-by-step explanation:

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3 years ago
Is this statement true or false explain why 6,203 > 6,320
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Step-by-step explanation:

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3 years ago
Cherie is jogging around a circular track. She
skelet666 [1.2K]

Answer:

Measure of minor angle JOG is 95.5^{\circ}

Step-by-step explanation:

Consider a circular track of radius 120 yards. Assume that Cherie starts from point J and runs 200 yards up to point G.  

\therefore m JG = 200 yards, JO=120 yards.  

Now the measure of minor arc is same as measure of central angle. Therefore minor angle is the central angle \angle JOG = \theta.

To calculate the central angle, use the arc length formula as follows.  

Arc\:Length\left(s\right) = r\:\theta  

Where \theta is measured in radian.

Substituting the value,

200=120\:\theta  

Dividing both side by 120,

\dfrac{200}{120}=\theta  

Reducing the fraction into lowest form by dividing numerator and denominator by 40.

\therefore \dfrac{5}{3}=\theta  

Therefore value of central angle is \angle JOG = \theta=\left(\dfrac{5}{3}\right)^{c}, since angle is in radian

Now convert radian into degree by using following formula,

1^{c}=\left(\dfrac{180}{\pi}\right)^{\circ}

So multiplying \theta with \left(\dfrac{180}{\pi}\right)^{\circ} to convert it into degree.

\left(\dfrac{5}{3}\right)^{c}=\left(\dfrac{5}{3}\right) \times \left(\dfrac{180}{\pi}\right)^{\circ}

Simplifying,

\therefore \theta = 95.49^{circ}

So to nearest tenth, \angle JOG=95.5^{circ}

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The average number of Instagram likes per day for Mr. Tutaks class was recorded and constructed into the following box plot
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Picture?

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3 years ago
Under which conditions does the molar volume of a gas decrease? A. at 273 K and at 2.0 atm. B. at 273 K and at 0.5 atm. C. at 40
Sloan [31]
We first assume that this gas is an ideal gas and we use the ideal gas equation to determine the answer. It is expressed as:

PV = nRT

Molar volume can be obtained from the equation by V/n.

V/n = RT/P

Therefore, the correct answer from the choices listed above is option A, <span>at 273 K and at 2.0 atm.</span>
7 0
3 years ago
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