5 horses with a combined weight of 6,240 pounds
horse trailer has a limit of 8,000 pounds of horse and tacks.
Find the weight of tack, t, for each horse that Cari can allow.
5t + 6,240 < 8,000
5t + 6,240 < 8,000
- 6,240 -6,240
5t < 1,760
<span>÷5 ÷5 </span>
t < 352
Each horse can carry a tack that weighs no more than 352 pounds.
Any tack that weighs beyond <span>352 </span>pounds is will exceed the maximum carrying capacity of the horse trailer.
Let's first see which box and whisker plots have a range of 17. The range is maximum-minimum. ( the last dot minus the first dot). For A. 20 - 4 = 16, so it can't be A. For B. 36-2 = 34, so it can't be B. For C. 36 - 19 = 17, so it could be C. And for D. 17 - 2 = 15, so it can't be D. C. must be the correct answer, but let's check if the interquartile range is 5. The IQR ( interquartile range) is the 3rd Quartile - the 1st Quartile. 33- 28 = 5. So, C. is the correct answer! Hope this helped!
There are 52 weeks in a year and if she gets paid every two weeks then divide 52 by 2 to get 26 so she would get paid 26 times a year so divide her annual salary by 26 to get $1,346.15 every other week. So her biweekly salary is $1,346.15.
4¹/₃x = ⁵/₁₂x - 6
3¹¹/₁₂x = -6
x = -1²⁵/₄₇
This is your answer:
<span>Trapezoid
JKLM is congruent to trapezoid J′K′L′M′ because you can map trapezoid
JKLM to trapezoid J′K′L′M′ by reflecting it across the line y = x and
then translating it 1 unit up, which is a sequence of rigid motions.</span>
