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2 years ago

I NEED HELP!!! ASAP!

Mathematics

1 answer:

iren2701 [21]2 years ago

7 0

I think the correct answer is B.

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1/4e-2f - 1/f-2e what is the answer?

timofeeve [1]

Answer:

(2.718282)−2f−

−(2)(2.718282)

−2f2−4.756993f−1

−8f2−19.027973f−4

7 0

2 years ago

A random sample of 200 people was taken. 90 of the people in the sample favored Candidate A. We are interested in determining wh

mafiozo [28]

Answer:

a. 1.44

Step-by-step explanation:

We are interested in determining whether or not the proportion of the population in favor of Candidate A is significantly more than 40%.

At the null hypothesis, it is tested if the proportion is of at most 40%, that is:

$H_0: p \leq 0.4$

At the alternative hypothesis, it is tested if the proportion is of more than 40%, that is:

$H_1: p > 0.4$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.4 is tested at the null hypothesis:

This means that $p = 0.4, \sigma = \sqrt{0.4*0.6}$

A random sample of 200 people was taken. 90 of the people in the sample favored Candidate A.

This means that:

$n = 200, X = \frac{90}{200} = 0.45$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.45 - 0.4}{\frac{\sqrt{0.4*0.6}}{\sqrt{200}}}$

$z = 1.44$

Thus the correct answer is given by option a.

8 0

2 years ago

Javier bought 2 adult movie tickets and 4 children’s movie tickets and spent a total of $46. If adult tickets cost $2 more than

Sergio [31]

The children's ticket would be $7 each and the adult ticket would be $9.

6 0

2 years ago

What is the interquartile range of this data set 2, 5, 9, 11, 18, 30, 42, 48, 71, 73, 81

Shtirlitz [24]

Answer:

I believe the answer is 62.

Step-by-step explanation:

Hope my answer has helped you!

8 0

2 years ago

A rectangular garden of area 75 ftö is bounded on three sides by a wall costing

ioda

A = L * W = 75 so L = 75/W Cost = 4W + 8(2L + W) = 4W + 16L + 8W = 12W + 16L = 12W + 1200/W C' = (12(W^2 - 100))/(W^2) = (12(W-10)(W+10))/(W^2) so W = 10 then L = 7.5

8 0

2 years ago