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liq [111]
3 years ago
12

manuel ate 1/3 of the crackers on a plate. his brother ate 1/4 of the crackers. there were 5 crackers left on the plate. how man

y crackers were on the plate to begin with
Mathematics
1 answer:
Neporo4naja [7]3 years ago
5 0

Answer:

there would have been 12 crackers on the plate at the start

Step-by-step explanation:

So 1/3 +1/4 = 7/12

Therefore 5/12 left on the plate …ie 5.

So total to start with

5/5×12=12

Ans 12

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Can somebody please help me. I have less then 10 mins to get the right answer
Dafna1 [17]

the bottom cube = 5in

middle=4

top =5

5+4+5=14in

8 0
4 years ago
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How to share four sandwiches with six people
dimaraw [331]
Cut each sandwich into pieces of thirds
 4 sandwiches x 3 pieces = 12 total pieces
--------------------
12 / 6 = 2
Everybody would get 2 pieces
3 0
3 years ago
Courtney walked from her house to the beach at a constant speed of 4 kilometers per hour, and then walked
RUDIKE [14]

<em><u>The system of equations that represents this situation are:</u></em>

q + p = 2

4q + 5p = 8

<em><u>Solution:</u></em>

Let  q be the number of hours it took Courtney to walk from her house to the beach

Let p be the number of hours it took her to walk from the beach to the park

<em><u>The entire walk took 2 hours</u></em>

Therefore,

q + p = 2 ------- eqn 1

<em><u>The  total distance Courtney walked was 8 kilometers</u></em>

Total distance = 8 km

Courtney walked from her house to the beach at a constant speed of 4 kilometers per hour

Then walked  from the beach to the park at a constant speed of 5 kilometers per hour

<em><u>Distance is given as:</u></em>

distance = speed \times time

<em><u>From her house to the beach:</u></em>

distance = 4 \times q = 4q

<em><u>From the beach to the park:</u></em>

distance = 5 \times p = 5p

We know that,

Total distance = 8 km

Therefore,

4q + 5p = 8 ------ eqn 2

<em><u>Thus the system of equations that represents this situation are:</u></em>

q + p = 2

4q + 5p = 8

8 0
4 years ago
Find the distance between the points (-21, 17) and (33, 17)
Norma-Jean [14]
Plug it into the distance formula.

d= (sqrt) (x2-x1)^2 +(y2-y1)^2

d= (sqrt) (17-17)^2 + (33-(-21)^2
d=(sqrt) (0)^2 + (33 +21)^2
d= (sqrt) (54)^2
d= (sqrt) 2916
d=54

The distance is 54 units. 

I hope this helps!
~kaikers
7 0
3 years ago
Midpoint of (16,5) and (-6,-9)?
Zigmanuir [339]

To solve this problem, we need to use the midpoint formula, where M = (x1+x2/2, y1+y2/2). To solve, we must plug in the given (x,y) values from our ordered pairs and then simplify, shown below:

(x1+x2/2, y1+y2/2)

( (16 + -6)/2, (5 + -9)/2 )

Now, we can begin to simplify by computing the addition in the numerators of both fractions.

(10/2, -4/2)

Next, we can finish the simplification process by dividing these fractions.

(5, -2)

Therefore, the midpoint of (16,5) and (-6,-9) is (5,-2).

Hope this helps!

8 0
3 years ago
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