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3 years ago

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manuel ate 1/3 of the crackers on a plate. his brother ate 1/4 of the crackers. there were 5 crackers left on the plate. how man

y crackers were on the plate to begin with

1 answer:

Neporo4naja [7]3 years ago

5 0

Answer:

there would have been 12 crackers on the plate at the start

Step-by-step explanation:

So 1/3 +1/4 = 7/12

Therefore 5/12 left on the plate …ie 5.

So total to start with

5/5×12=12

Ans 12

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Please answer this question !! Will give brainliest !

ICE Princess25 [194]

Answer & Step-by-step explanation:

In order to find the y-intercept of this equation, we must turn this equation into a slope-intercept equation. The equation for slope-intercept form is <em>y=mx+b. </em>We can do this by using these steps. Our goal is to get y by itself on one side.

6x - 2y - 9 = 0

Step 1: Add 9 on both sides of the equation.

6x - 2y = 9

Step 2: Subtract 6x on both sides of the equation. Once you subtract, make sure you put the -6x in front of 9 so we are following the rules of variables and exponents.

-2y = -6x + 9

Step 3: Divide -2 on both sides of the equation.

y = 3x - $\frac{9}{2}$

So, the y-intercept is - $\frac{9}{2}$

4 0

3 years ago

N/4 + 12 =18 i will give brainllest

Hoochie [10]

Answer:

n = 24

Step-by-step explanation:

subtract 12

n/4 = 6

multiply by 4

n = 24

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3 years ago

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-0.6w=2.4<br> Please answer<br> Hggjigj

SashulF [63]

Final Answer: $w = -4$

Steps/Reasons/Explanation:

Question: Solve $-0.6w = 2.4$ .

<u>Step 1</u>: Divide both sides by $-0.6$ .

$w = -\frac{2.4}{0.6}$

<u>Step 2</u>: Simplify $\frac{2.4}{0.6}$ to $4$ .

$w = -4$

~I hope I helped you :)~

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3 years ago

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The temperature dropped from 6 Celsius to -5 Celsius.How many degrees did the temperature drop?

kakasveta [241]

-11 degrees. 6+5=11, and it went down, so negative 11 degrees

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3 years ago

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Given that (ax^2 + bx + 3) (x + d) = x^3 + 6x^2 + 11x + 12<br> a + 2b - d = ?

Mariulka [41]

Answer:

Let's solve for a.

(ax2+bx+3)(x+d)=x3+6x2+11x+12a+2b−d

Step 1: Add -12a to both sides.

adx2+ax3+bdx+bx2+3d+3x+−12a=x3+6x2+12a+2b−d+11x+−12a

adx2+ax3+bdx+bx2−12a+3d+3x=x3+6x2+2b−d+11x

Step 2: Add -bdx to both sides.

adx2+ax3+bdx+bx2−12a+3d+3x+−bdx=x3+6x2+2b−d+11x+−bdx

adx2+ax3+bx2−12a+3d+3x=−bdx+x3+6x2+2b−d+11x

Step 3: Add -bx^2 to both sides.

adx2+ax3+bx2−12a+3d+3x+−bx2=−bdx+x3+6x2+2b−d+11x+−bx2

adx2+ax3−12a+3d+3x=−bdx−bx2+x3+6x2+2b−d+11x

Step 4: Add -3d to both sides.

adx2+ax3−12a+3d+3x+−3d=−bdx−bx2+x3+6x2+2b−d+11x+−3d

adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

adx2+ax3−12a+3x+−3x=−bdx−bx2+x3+6x2+2b−4d+11x+−3x

adx2+ax3−12a=−bdx−bx2+x3+6x2+2b−4d+8x

Step 6: Factor out variable a.

a(dx2+x3−12)=−bdx−bx2+x3+6x2+2b−4d+8x

Step 7: Divide both sides by dx^2+x^3-12.

a(dx2+x3−12)

dx2+x3−12

=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

a=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

Answer:

a=

−bdx−bx2+x3+6x2+2b−4d+8x/

dx2+x3−12

Step-by-step explanation:

8 0

3 years ago