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DedPeter [7]
3 years ago
15

What happens to lava as its temperature increases?

Physics
1 answer:
kvasek [131]3 years ago
4 0
I will assume you mean liquid lava, that is, magma that has been expelled by a volcano, and is flowing downhill, until it cools and solidifies as lava rock. Liquids typically have a generally inverse relationship between viscosity (resistance to flow) and temperature. That is, as the temperature increases, viscosity generally decreases (i.e., the lava gets “thinner” and “runnier”), as Gopismhas said. However, generally, in nature, lava doesn’t increase in temperature, but rather cools as it is expelled and flows downhill, and thus it is getting more and more viscous…until it solidifies.
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Describe a line that indicates moving backward on a graph
Vladimir [108]

Answer:

time speed accelaration negatives backwards

Explanation:

4 0
3 years ago
a radio controlled car rolls 10 m south then reverses direction and rolls 8 m north the car traveled a distance of 18 m and has
EastWind [94]

The displacement is 2 m south

Explanation:

Distance and displacement are two different quantities:

  • Distance is the total length of the path covered by an object during its motion, regardless of the direction. It is a scalar quantity
  • Displacement is a vector connecting the initial position to the final position of motion of an object. The magnitude of the displacement is the distance in a straight line between the two points

For the car in this problem, the motion is:

10 m south

8 m north

Taking north as positive direction, we can describe the two parts of the motion as

d_1 = -10 m

d_2 = +8 m

Therefore,  the final position of the car with respect to the original position is

x_f = -10 + 8 = -2 m

which means 2 m south: so, the displacement of the car is 2 m south.

Learn more about  distance and displacement:

brainly.com/question/3969582

#LearnwithBrainly

5 0
3 years ago
A toy cannon uses a spring to project a 5.35-g soft rubber ball. The spring is originally compressed by 5.08 cm and has a force
Elenna [48]

Answer:

a) the velocity is v=1.385 m/s

b) the ball has its maximum speed at 4.68 cm away from its compressed position

c)  the maximum speed is 1.78 m/s

Explanation:

if we do an energy balance over the ball, the potencial energy given by the compressed spring is converted into kinetic energy and loss of energy due to friction, therefore

we can formulate this considering that the work of the friction force is equal to to the energy loss of the ball

W fr = - ΔE = - ΔU - ΔK = Ui - Uf + Kf - Ki

therefore

Ui + Ki = Uf + Kf + W fr  

where U represents potencial energy of the compressed spring , K is the kinetic energy W fr is the work done by the friction force. i represents inicial state, and f final state.

since

U= 1/2 k x² , K= 1/2 m v²  , W fr = F*L

X= compression length , L= horizontal distance covered

therefore

Ui + Ki = Uf + Kf + W fr

1/2 k xi² + 1/2 m vi² = 1/2 k x² + 1/2 m vf² + F*L

a) choosing our inicial state as the compressed state , the initial kinetic energy is Ki=0 and in the final state the ball is no longer pushed by the spring thus Uf=0

1/2 k X² + 0 = 0 + 1/2 m v² + F*L

1/2 m v² = 1/2 k X² - F*L

v = √[(k/m)x² -(2F/m)*L] = √[(8.07N/m/5.35*10^-3 Kg)*(-0.0508m)² -(2*0.033N/5.35*10^-3 Kg)*(0.16 m)] = 1.385 m/s

b) in any point x , and since L= d-(X-x) , d = distance where is no pushed by the spring.

1/2 k X² + 0 = 1/2 k x² + 1/2 m v² + F*[d-(X+x)]

1/2 m v² =1/2 k X²-1/2 k x² - F*[d-(X-x)] = (1/2 k X²+ F*X) - 1/2k x² - F*x + F*d

taking the derivative

dKf/dx = -kx - F = 0 → x = -F/k = -0.033N/8.07 N/m = -4.089*10^-3 m = -0.4cm

at x m = -0.4 cm the velocity is maximum

therefore is 5.08 cm-0.4 cm=4.68 cm away from the compressed position

c) the maximum speed is

1/2 m v max² = (1/2 k X²+ F*X) - 1/2k x m² - F*(x m) + 0

v =√[ (k/m) (X²-xm²) + (2F/m)(X-xm) ] = √[(8.07N/m/5.35*10^-3 Kg)*[(-0.0508m)² - (-0.004m)²] + (2*0.033N/5.35*10^-3 Kg)*(-0.0508m-(-0.004m)] = 1.78 m/s

4 0
3 years ago
A 13.0 g piece of Styrofoam carries a net charge of â5.40 μC and floats above the center of a large horizontal sheet of plastic
kati45 [8]

Answer:

σ =4.180×10^{-9} C/m^2

Explanation:

electric field due to non conducting sheet is

E=\frac{\sigma}{2\epsilon_0}

the force acting on the piece of Styrofoam

Eq= mg

⇒E= mg/q

now,

\frac{mg}{q} = \frac{\sigma}{2\epsilon_0}

⇒\sigma= \frac{2mg\epsilon_0}{q}

\sigma= \frac{2\times0.013\times9.81\times8.85\times10^{-12}}{5.40\times10^{-4}}

charge per unit area (in C/m2) on the plastic sheet σ =4.180×10^{-9} C/m^2

6 0
4 years ago
a 10. kg ball thrown into the air. it is going 3.0 m/s when thrown. how much potential energy will it have at the top?
Sever21 [200]

Answer:

45 j

Explanation:

At the top, the KE will have been converted to PE

KE = 1/2 mv^2 =PEat-top = 1/2 10 *3^9 = 45 j

6 0
2 years ago
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