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Sever21 [200]
3 years ago
5

Explain test that would be made to find and whether such a

Physics
1 answer:
fredd [130]3 years ago
7 0

Answer:

slightly tilt the barometer below barometric height.if the mercury fills up the space,then there Is no air.if it doesnt,then there is air

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A cement factory emits 900 kilograms of CO2 to produce 1,000 kilograms of cement. A fully grown tree removes six kilograms of CO
Dmitriy789 [7]
<h3><u>Answer;</u></h3>

To make the factory carbon neutral, the owners need to grow<em><u> 15000 trees</u></em> over an area of land measuring <em><u>75 acres</u></em>

<h3><u>Explanation and solution;</u></h3>

From the information;

900 kg CO2 = 1000 kg Cement

1 tree = 6 kg CO2

1 acre = 200 trees

<em>100000 kg Cement will require;</em>

<em>=(900 × 100000)/1000</em>

<em>= 90,000 kg of CO2</em>

<em>But 1 tree = 6 kg of CO2</em>

<em>Number of trees = 90,000/6</em>

<em>                            = 15,000 trees </em>

<em>But, 1 acre = 200 trees</em>

<em>Number of acres = 15,000/200</em>

<em>                             = 75 acres of land </em>

Therefore;

To make the factory carbon neutral, the owners need to grow<em><u> 15000 trees</u></em> over an area of land measuring <em><u>75 acres</u></em>

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3 years ago
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Organ system that removes waste from your body
JulijaS [17]

Answer:

Digestive System

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WIL GIVE BRAINLISEST PLEASE HELP SPEED ACCELERATION GRAPHS LABEL THE GRAPHS PLEASEEeeee
Varvara68 [4.7K]

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Take the numbers and fill them in graph.

Plot time as X and speed as Y and afterward join then like a line graph.

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3 years ago
What is the definition of binary star system
lakkis [162]
Is a system of two objects in space which are so close that their gravitational  interaction causes them to orbit  about a common center of mass.
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3 years ago
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A 10-g bullet moving horizontally with a speed of 1.8 km/s strikes and passes through a 5.0-kg block initially at rest on a hori
marshall27 [118]

Answer:

K_2=6.4J

Explanation:

According to the principle of conservation of momentum, we have:

\Delta p=0\\p_i=p_f\\m_1v_1_i +m_2v_2_i=m_1v_1_f+m_2v_2_f

Here 1 is for the bullet and 2 is for the block. Since the block is initially at rest v_i_2=0. Solving for v_2_f and replacing the given values:

v_2_f=\frac{m_1(v_1_i-v_1_f)}{m_2}\\v_2_f=\frac{10*10^{-3}kg(1.8\frac{km}{s}-1\frac{km}{s})}{5kg}\\v_2_f=0.0016\frac{km}{s}*\frac{1000m}{1km}=1.6\frac{m}{s}

The kinetic energy of the block is given by:

K_2=\frac{m_2(v_f_2)^2}{2}\\K_2=\frac{5kg(1.6\frac{m}{s})^2}{2}\\K_2=6.4J

3 0
3 years ago
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