Many materials produce static charge
Answer:
the force will decrease to 3/4 of its original value.
Explanation:
The initial electric force between the two charges is:
![F = k \frac{q\cdot q}{r^2}](https://tex.z-dn.net/?f=F%20%3D%20k%20%5Cfrac%7Bq%5Ccdot%20q%7D%7Br%5E2%7D)
where
k is the Coulomb's constant
q is the magnitude of each charge
r is their separation
Later, half of one charge is transferred to the other charge; this means that one charge will have a charge of
![q+\frac{q}{2}=\frac{3}{2}q](https://tex.z-dn.net/?f=q%2B%5Cfrac%7Bq%7D%7B2%7D%3D%5Cfrac%7B3%7D%7B2%7Dq)
while the other charge will be
![q-\frac{q}{2}=\frac{q}{2}](https://tex.z-dn.net/?f=q-%5Cfrac%7Bq%7D%7B2%7D%3D%5Cfrac%7Bq%7D%7B2%7D)
So, the new force will be
![F' = k \frac{(\frac{q}{2})\cdot (\frac{3}{2}q)}{r^2}=\frac{3}{4} (k\frac{q\cdot q}{r^2})=\frac{3}{4}F](https://tex.z-dn.net/?f=F%27%20%3D%20k%20%5Cfrac%7B%28%5Cfrac%7Bq%7D%7B2%7D%29%5Ccdot%20%28%5Cfrac%7B3%7D%7B2%7Dq%29%7D%7Br%5E2%7D%3D%5Cfrac%7B3%7D%7B4%7D%20%28k%5Cfrac%7Bq%5Ccdot%20q%7D%7Br%5E2%7D%29%3D%5Cfrac%7B3%7D%7B4%7DF)
So, the force will decrease to 3/4 of its original value.
The question is asking to describe and state and calculate what do the observer on the earth measure for the speed of the laser beam, and base on my research, the answer would be v = 1bc, I hope you are satisfied with my answer and feel free to ask for more