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2 years ago

Objects 1 and 2 attract each other with a gravitational force

Physics

1 answer:

Katena32 [7]2 years ago

7 0

The new gravitational force of the two objects will be 432 N.

The given parameters:

Force between object 1 and object 2, F = 18 N

Let the mass of object 1 = m1
Let the mass of object 2 = m2
Let the distance between the two object = r

The gravitational force between the two objects is calculated by applying Newton's law of universal gravitation;

$F = \frac{Gm_1m_2}{r^2} \\\\G = \frac{Fr^2}{m_1m_2}\\\\G = \frac{Gm_1m_2}{r^2} \\\\G = \frac{18r^2}{m_1m_2}$

when the mass of the object 1 = 2m1
mass of the object 2 = 3m2
distance between the two object = ¹/₂r

$\frac{18r^2}{m_1 m_2 } = \frac{F_2(\frac{1}{2}r)^2 }{2m_1 \times 3m_2} \\\\\frac{18r^2}{m_1 m_2 } = \frac{F_2 \times r^2}{4 \times 2m_1 \times 3m_2} \\\\\frac{18r^2\times 4 \times 2m_1 \times 3m_2}{m_1 m_2\times r^2 } = F_2\\\\432 \ N = F_2$

Thus, the new gravitational force of the two objects will be 432 N.

Learn more about Newton's law of universal gravitation here: brainly.com/question/9373839

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Answer:

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At this point, we can start answering!

1a. The pressure at A is - not counting atmosferic pressure - $1000 * 10 * 1 = 10^4 Pa$ , while in B is $1000*10*2 = 2*10^4 Pa$ , so it's half of it.

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1c. Ditto. Same depth? same pressure!

1d. Usual equation, this time density is 800. Pressure is $800*10*2 = 1,6*10^4 Pa$ : Since the density is 4/5 of water, the pressure is also 4/5 of the one exerted by water

2a. The volume is simply the product, so $4m*3m*2m = 24m^3$

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4 0

2 years ago

A screen is placed 1.20m behind a single slit. The central maximum in the resulting diffraction pattern on the screen is 1.40cm

andrew11 [14]

Answer:

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Explanation:

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m = Order

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$\beta_1=\dfrac{y_1}{2}\\\Rightarrow \beta_1=\dfrac{1.4}{2}\\\Rightarrow \beta_1=0.7\ cm$

Fringe width is also given by

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For second order

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