Answer:
The fourth term of the expansion is -220 * x^9 * y^3
Step-by-step explanation:
Question:
Find the fourth term in (x-y)^12
Solution:
Notation: "n choose k", or combination of k objects from n objects,
C(n,k) = n! / ( k! (n-k)! )
For example, C(12,4) = 12! / (4! 8!) = 495
Using the binomial expansion formula
(a+b)^n
= C(n,0)a^n + C(n,1)a^(n-1)b + C(n,2)a^(n-2)b^2 + C(n,3)a^(n-3)b^3 + C(n,4)a^(n-4)b^4 +....+C(n,n)b^n
For (x-y)^12, n=12, k=3, a=x, b=-y, and the fourth term is
C(n,3)a^(n-3)b^3
=C(12,3) * x^(12-3) * (-y)^(3)
= 220*x^9*(-y)^3
= -220 * x^9 * y^3
Answer:
7x +5
Step-by-step explanation:
Mason works h hours each day during the 5-day workweek. He also works 5 hours on the weekend. Write an algebraic expression for the number of hours Mason works each week.
"h hours each day in the week"
There are 7 days, so 7 × x.
"5 hours on the weekend"
5
So, this can be written as 7x + 5.
<em>Hope I helped, have a nice day!</em>
<em> -Aadi x</em>
The plane will descend 900 ft every minute
This is the case because we divide 4500 by 5
Hope this helps and have a great day!
Answer:
More detail needed
Step-by-step explanation:
The question is not clear, therefor there is no way to solve it.
Answer: discrete.
Step-by-step explanation:
Discrete variable
It is a variable whose value is evaluated by counting.
Example: Number of books published in a month.
Continuous variable
It is a variable whose value is evaluated by measuring ( not countable).
Example: Distance: 1.52 m
Since the number of dental visits a randomly chosen person had for the past 5 years is a countable.
here, Variable: Let X =number of dental visits a randomly chosen person had for the past 5 years
So, the random variable described is discrete.
