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2 years ago

What is the common denominator of 1/8 and 11/6

Mathematics

1 answer:

sashaice [31]2 years ago

6 0

Answer:

Step-by-step explanation:

What we're asking ourselves here is... what is the least number possible that we can get as a denominator for both 1/8 and 11/6 without changing the value of either fraction.

Let's list off the first couple multiples of 8 and 6 to see the lowest number they can both become through multiplying:

8, 16, 24, 32, 40

6, 12, 18, 24, 30

Notice that both have a multiple of 24. This is the answer to the question. If you need more help, let me know! :)

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Write in point-slope form an equation of the line passing through (-4, 10) and (-6, 15). Show your work.

Neporo4naja [7]

This is how it is done. Let me know if you have questions...

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2 years ago

A box contains 3 green marbles, 5 blue marbles, and 7 red marbles. Three marbles are selected at random from the box, one at a t

USPshnik [31]

Answer:

The probability is $P(K) = \frac{ 28 }{195}$

Step-by-step explanation:

From the question we are told that

The number of green marbles is $n_g = 3$

The number of red marbles is $n_b = 5$

The number of red marbles is $n_r = 7$

Generally the total number of marbles is mathematically represented as

$n_t = n_r + n_g + n_ b$

$n_t = 7 + 3 + 5$

$n_t = 5$

Generally total number of marbles that are not red is

$n_k = n_g + n_ b$

=> $n_k = 3 + 5$

=> $n_k = 8$

The probability of the first ball not being red is mathematically represented as

$P(r') = \frac{n_k}{n_t}$

=> $P(r') = \frac{ 8}{15}$

The probability of the second ball not being red is mathematically represented as

$P(r'') = \frac{n_k - 1}{n_t -1}$

=> $P(r'') = \frac{ 8 -1 }{15-1}$ (the subtraction is because the marbles where selected without replacement )

=> $P(r'') = \frac{ 7 }{14}$

The probability that the first two balls is not red is mathematically represented as

$P(R) = P(r') * P(r'')$

=> $P(R) = \frac{ 8}{15} * \frac{ 7 }{14}$

=> $P(R) = \frac{ 8 }{30}$

The probability of the third ball being red is mathematically represented as

$P(r) = \frac{n_r}{ n_t -2}$ (the subtraction is because the marbles where selected without replacement )

$P(r) = \frac{7}{ 15 -2}$

=> $P(r) = \frac{7}{ 13}$

Generally the probability of the first two marble not being red and the third marble being red is mathematically represented as

$P(K) = P(R) * P(r)$

$P(K) = \frac{ 8 }{30} * \frac{7}{ 13}$

=> $P(K) = \frac{ 28 }{195}$

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2 years ago

DEFINE ALL OF THESE, ONE SENTENCE EACH, PLEASE

coldgirl [10]

Answers:

These are the three major and pure mathematical problems that are unsolved when it comes to large numbers.

The Kissing Number Problem: It is a sphere packing problem that includes spheres. Group spheres are packed in space or region has kissing numbers. The kissing numbers are the number of spheres touched by a sphere.

The Unknotting Problem: It the algorithmic recognition of the unknot that can be achieved from a knot. It defined the algorithm that can be used between the unknot and knot representation of a closely looped rope.

The Large Cardinal Project: it says that infinite sets come in different sizes and they are represented with Hebrew letter aleph. Also, these sets are named based on their sizes. Naming starts from small-0 and further, prefixed aleph before them. eg: aleph-zero.

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2 years ago

Geometry! Please help with math!

Angelina_Jolie [31]

I am not for sure how to do this just yet when I figher it out I will try to help you.

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3 years ago

Angle 1 and angle 2 are vertical angles. If m angle 1 = (8x+12)° and m angle 2 = (3x+37)° find the measure for each angle.

laila [671]

Vertically opposite angles are always equal.

Given angles are (8x+12)° and (3x+37)°

=> (8x+12)° = (3x + 37)°

=> 8x - 3x = 37-12

=> 5x = 25

=> x = 25/5 = 5°

Angle 1 = (8x+12)° = (8(5)+12) = 40+12 = 52°

Angle 2 = (3x + 37)° = (3(5)+37)° = 15+37 = 52°

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1 year ago