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4 years ago

How long does it take each horse to run a mile

Mathematics

1 answer:

GenaCL600 [577]4 years ago

8 0

I say.............2-6 mins
Lol

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last year Patrick paid £2534 for his annual train ticket this year he has to pay £2612 for his annual train ticket. work out the

Aleonysh [2.5K]

Answer:

Percentage increase in the cost of his train ticket = 3% (Approx.)

Step-by-step explanation:

Given:

Cost of annual ticket paid by Patrick last year = £2,534

Cost of annual ticket paid by Patrick current year = £2,612

Find:

Percentage increase in the cost of his train ticket

Computation:

Percentage increase = [(Current - Base) / Base]100

Percentage increase in the cost of his train ticket = [(2,612 - 2,534) / 2,534]100

Percentage increase in the cost of his train ticket = [(78) / 2,534]100

Percentage increase in the cost of his train ticket = [0.03078]100

Percentage increase in the cost of his train ticket = 3.078

Percentage increase in the cost of his train ticket = 3% (Approx.)

3 0

3 years ago

Of the 125 guests invited to a wedding, 104 attended the wedding.What percent of the invited guests attended the wedding?

Ganezh [65]

Divide the number of guest that came by the number of guests invited: 104/125=.832 or 83%. 83% of the invited guests were there :)

6 0

3 years ago

ANSWER ASAP PLEASE !!!AND CORRECT!!<br> OTHER ANSWER CHOICE IS 19 feet, 6 inches.

DiKsa [7]

well you know that the yellow rope is 18' shorter then the white rope X 2,

so you would take 101/2 feet and add 18 inches, then you would need to divide that by two to get how long the white one is.

10 1/2 feet + 18 inches = 12 feet

12 feet divided by 2 is 6 feet

8 0

3 years ago

Which value, when placed in the box, would result in a system of equations with infinitly many solutions? Y=2x - 5 2y-4x=

Nezavi [6.7K]

Given:

The system of equations is

$y=2x-5$

$2y-4x=?$

To find:

The missing value for which the given system of equations have infinitely many solutions.

Solution:

Let the missing value be k.

We have,

$y=2x-5$

$2y-4x=k$

Taking all the terms on the left side, the given equations can be rewritten as

$-2x+y+5=0$

$-4x+2y-k=0$

The system of equations $a_1x+b_1y+c_1=0$ and $a_2x+b_2y+c_2=0$ have infinitely many solutions if

$\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}$

We have,

$a_1=-2,b_1=1,c_1=5$

$a_2=-4,b_2=2,c_2=-k$

Now,

$\dfrac{-2}{-4}=\dfrac{1}{2}=\dfrac{5}{-k}$

$\dfrac{1}{2}=\dfrac{1}{2}=\dfrac{5}{-k}$

$\dfrac{1}{2}=\dfrac{5}{-k}$

On cross multiplication, we get

$-k=10$

$k=-10$

Therefore, the missing value is -10.

6 0

3 years ago

What’s the answer to A

NISA [10]

Answer:60

Step-by-step explanation:

plz like

5 0

2 years ago