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zysi [14]
4 years ago
10

Which of the following is a dynamic lot-sizing technique that calculates the order quantity by comparing the carrying cost and t

he setup (or ordering) costs for various lot sizes and then selects the lot size in which these are most nearly equal?
a. Least total cost
b. Kanban
c. MRP
d. Just-in-time system
e. Least unit cost
Computers and Technology
1 answer:
Zarrin [17]4 years ago
5 0

Answer:

C

Explanation:

Because

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Write a C++ program to find K largest elements in a given array of integers. For eeample, if K is 3, then your program should ou
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Answer:

// C++ program to find k largest elements in the array

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// variable

int n,k;

cout<<"Enter the number of elements of array:";

// read the value of n

cin>>n;

// declare the array of size n

int arr[n];

cout<<"Enter the elements of array:";

// read the elements of array

for(int a=0;a<n;a++)

{

   cin>>arr[a];

}

cout<<"Enter the value of K:";

cin>>k;

// call the function to perform selection Sort

sort(arr, arr+n);

cout << k<<" largest elements of the array are: ";

// print k largest elements of the array

for (int i=n-1; i>n-k-1; i--)

cout << arr[i] << " ";

return 0;

}

Explanation:

Read the number of elements in the array.Then create an array of size "n" and read  n elements of the array.Sort the array in ascending array.Then Read the value of  k from user.Find the k Elements from the end of the array.This will be the k  largest elements of the array.

Output:

Enter the number of elements of array:8                                                                                    

Enter the elements of array:34 8 75 99 12 7 5 55                                                                          

Enter the value of K:3                                                                                                    

3 largest elements of the array are: 99 75 55

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3 years ago
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